Answer:
C. x=5/2
Step-by-step explanation:
-2x+10x=34-14
(8x=20 ) /:8
x=5/2
There are 160 fluid ounces in 5 quarts. Because there are 32 fluid ounces in 1 quart multiply that by 5 and you get 160. Your welcome!!!
The ball will be fastest right before it hits the ground because of gravity.
First, let's find the value of t where the ball hits the ground.
-8t²+25 = 0
-8t² = -25
t² =

t =

Note: t has to be positive, which is why there is no positive/negative symbol.
Now, let's calculate the derivative of this function. The derivative will give us the speed of the ball for time t.
d/dx = -16t
Now, let's plug in the value of t
-16 (

}
=

=

Take the absolute value of that because speed can't be negative

That's the speed of the ball. You can convert that into decimal if you'd like.
Have an awesome day! :)
![\bf \stackrel{\textit{testing for the x-axis symmetry, }\theta =-\theta }{r=8cos(3\theta )\implies r=8cos[3(-\theta)]}\implies r=8cos(-3\theta) \\\\\\ r=8cos(3\theta)~~\boxed{\checkmark}~~\impliedby \stackrel{\textit{trigonometry symmetry identities}}{cos(\theta)=cos(-\theta)}\\\\ -------------------------------](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Btesting%20for%20the%20x-axis%20symmetry%2C%20%7D%5Ctheta%20%3D-%5Ctheta%20%7D%7Br%3D8cos%283%5Ctheta%20%29%5Cimplies%20r%3D8cos%5B3%28-%5Ctheta%29%5D%7D%5Cimplies%20r%3D8cos%28-3%5Ctheta%29%0A%5C%5C%5C%5C%5C%5C%0Ar%3D8cos%283%5Ctheta%29~~%5Cboxed%7B%5Ccheckmark%7D~~%5Cimpliedby%20%5Cstackrel%7B%5Ctextit%7Btrigonometry%20symmetry%20identities%7D%7D%7Bcos%28%5Ctheta%29%3Dcos%28-%5Ctheta%29%7D%5C%5C%5C%5C%0A-------------------------------)
![\bf \stackrel{\textit{testing for the y-axis symmetry, }\theta =\pi -\theta }{r=8cos(3\theta )\implies r=8cos[3(\pi -\theta)]}\implies r=8cos(3\pi -3\theta)\boxed{\otimes}\\\\ -------------------------------\\\\ \stackrel{\textit{testing for the origin symmetry, }\theta =\pi +\theta }{r=8cos(3\theta )\implies r=8cos[3(\pi +\theta)]}\implies r=8cos(3\pi +3\theta)\boxed{\otimes}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Btesting%20for%20the%20y-axis%20symmetry%2C%20%7D%5Ctheta%20%3D%5Cpi%20-%5Ctheta%20%7D%7Br%3D8cos%283%5Ctheta%20%29%5Cimplies%20r%3D8cos%5B3%28%5Cpi%20-%5Ctheta%29%5D%7D%5Cimplies%20r%3D8cos%283%5Cpi%20-3%5Ctheta%29%5Cboxed%7B%5Cotimes%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%5Cstackrel%7B%5Ctextit%7Btesting%20for%20the%20origin%20symmetry%2C%20%7D%5Ctheta%20%3D%5Cpi%20%2B%5Ctheta%20%7D%7Br%3D8cos%283%5Ctheta%20%29%5Cimplies%20r%3D8cos%5B3%28%5Cpi%20%2B%5Ctheta%29%5D%7D%5Cimplies%20r%3D8cos%283%5Cpi%20%2B3%5Ctheta%29%5Cboxed%7B%5Cotimes%7D)
so as you can see, since the x-axis test yielded the same original expression, it has symmetry with the x-axis, or namely the "polar axis".