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ss7ja [257]
2 years ago
11

ASAP AWNSER PLSSS!

Mathematics
2 answers:
Lisa [10]2 years ago
8 0

Answer:

it is 2 spaces away. a positive number from zero would be +2 and a negative number would be -2

Step-by-step explanation:

MArishka [77]2 years ago
4 0
A I did the quiz and got it rights so yea I think it’s a
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Solve the following system of equations below using any method.
Vitek1552 [10]

Answer:

(1,2) or equation form: x=1 y=2

Step-by-step explanation:

Used system of equations and doubled checked!

4 0
3 years ago
Archie has a bag of grass seed that he will use to cover a new field. The bag contains information about the area of the ground
gladu [14]

25:1 is the constant of proportionality between the number of square yards of grouse to be covered and the number of scoops of grass seed needed.

This was found by reducing the any of the 4 provided proportions, each would end up leading you to 25/1


8 0
3 years ago
Help me with algebra 2 homework
valkas [14]
-10y + 9x = - 9....A
10y + 5x = - 5.....B

You should see right away that -10y and 10y cancel out.

We are left with

14x = -14

x = -14/14

x = -1

Plug x = -1 into EITHER equation A or B to find y.

I will use equation A.

-10y + 9(-1) = - 9

-10y - 9 = - 9

-10y = - 9 + 9

- 10y = 0

y = 0/-10

y = 0

Done!
6 0
3 years ago
What is the area of triangle PQR?
Rufina [12.5K]
Area = 1/2 bh = 1/2(86)(52) = 2236
answer
2236 square inches
7 0
4 years ago
Read 2 more answers
Can you express 14 17 ?23 as a linear combination of V?<br><br> V= (2 1 -1), (1 -1 2), (4 5 -7)
KATRIN_1 [288]

Answer:

No ,we cannot express 14,17,23 as a linear combination of V

Step-by-step explanation:

Here 14,17,23 can be written as linear combination of V if we have a,b and c all non zero such that

(14,17,23) = a(2,1,-1)+b(1,-1,2)+c(4,5,-7)

(14,17,23) = (2a,a,-a)+(b,-b,2b)+(4c,5c,-7c)   [ scalar multiplication ]

(14,17,23)= (2a+b+4c,a-b+5c,-a+2b-7c)    [ vector addition ]

2a+b+4c = 14               equation 1

a-b+5c= 17                  equation 2

-a+2b-7c =23             equation 3

Here we  have three simultaneous equations

Since equation 2 and 3 has sign of a is opposite  with coefficient 1,adding both equations,we get

b-2c = 40

multiplying equation equation 3 by 2 and adding it to equation 1 in order to eliminate the term a

2a+b+4c=14

-2a+4b-14c=46

adding 5b-10c = 60

           divide it both sides by 5 ,we get

              b -2c = 12

here we see that  left side of two equations same but right side is not same

therefore solution doesnt exist .

Moreover given set of Vectors in V are not linear independent

since their determinant is zero

in order to write linear combination ,we need to have linearly independent vectors

there exist not values of a  ,and c

therefore we cannot express 14,17,23 as linear combination of V

8 0
3 years ago
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