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tamaranim1 [39]
2 years ago
8

Which operation is not efficiently supported by heaps?

Computers and Technology
1 answer:
vodka [1.7K]2 years ago
6 0

In the case above, the operation is not efficiently supported by heaps is Find.

<h3>What are heap operations?</h3>

The operation that are known to often use heaps are:

  • Heapify
  • Find-max (or Find-min)
  • Insertion, etc.

Therefore, In the case above, the operation is not efficiently supported by heaps is Find.

See full question below

Which operation is not efficiently supported by heaps?

a. DeleteMin

b. Find

c. FindMin

d. Insert

e. all of the above are sufficiently supported

Learn more about operation from

brainly.com/question/24214198

#SPJ11

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Which of the following is an example of plagiarism? A. Listing someone as an author who did not actually contribute to the publi
Nata [24]

Answer:

C. <em>Presenting someone else’s ideas or words and claiming them as one's own.</em>

Explanation:

The correct option is <em>C. Presenting someone else’s ideas or words and claiming them as one's own. </em>

The definition of <em>Plagiarism </em>indicates that stealing and passing off ideas or words created and / or developed by others and pretending or signifying that such words or ideas are one´s one is considering an act of plagiarism.

3 0
3 years ago
Messages that have been accessed or viewed in the Reading pane are automatically marked in Outlook and the message subject is no
vivado [14]

Answer:

Mark as Unread

Explanation:

I just know

5 0
3 years ago
Read 2 more answers
Finish the sentence. If the IP address and MAC address are parameters of layer 3 and layer 2, respectively, a port number is a p
stepan [7]

Answer:

Layer 4

Explanation:

MAC address works at the data link layer (layer 2) of the OSI model. Mac address allows computers to uniquely identify themselves in the network

IP Address is a logical address that works at the network layer of OSI model (layer 3) (actually the IP layer of TCP/IP model).

The port number works at the transport layer of the OSI model (layer 4).The port number uses sequence number to send segments to the correct application thereby ensuring they arrive in the correct order.

7 0
3 years ago
When processing all the elements of row i of a two-dimensional array named grades using a for loop with variable j, what is the
kykrilka [37]

Answer:

D

Explanation:

Two dimensional array contain both rows and columns. Each row represented one record and each column represent one filed in that record.

for ex: int grades[5][3];

here array grades contains 5 rows and in each row we have 3 columns

if we have grades[i][j] then " i " represents number of rows and j represents the number of columns in that row.

j<grades[i].length represents i=0 to 2[here no of columns are 3, array index starts from 0 to 2]

The Answer is D

8 0
3 years ago
Item = "quesadilla"
jok3333 [9.3K]

Answer:

item = "quesadilla"

meat = "steak"

queso = False

guacamole = False

double_meat = False

base_price = 4.5

if item == "quesadilla":

base_price = 4.0

elif item == "burrito":

base_price = 5.0

if meat == "steak" or meat == "pork":

base_price += 0.50

if meat == "steak" and double_meat:

base_price += 1.50

elif meat == "pork" and double_meat:

base_price += 1.50

elif double_meat:

base_price += 1.0

if guacamole:

base_price += 1.0

if queso and item != "nachos":

base_price += 1.0

print(base_price)

Explanation:

  • Use a conditional statement to check if meat is steak or pork then add 0.50 to base_price .
  • Check if the meat is steak or pork, then double_meat adds 1.50 or 1.0 otherwise .
  • Check if meat is steak and its double_meat , then add 1.50  and if its for guacamole, then add 1.00 to base_price . If queso is there and item is not nachos, add 1.00 to base_price .
  • Finally when item is nachos, no need to add any money to base_price .

7 0
3 years ago
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