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Alla [95]
2 years ago
12

Im giving brainlest!

Mathematics
1 answer:
wlad13 [49]2 years ago
5 0

The statement that is true concerning the function of the table compared to the graph is that the graphed function has a greater maximum value. That is option D.

<h3>Comparison of table function and graph</h3>

From the graph, the maximum value is =0.5 while the minimum value cannot be determined.

From the table the maximum value is -3 while the minimum value is -24.

Therefore, the statement that is true concerning the function of the table compared to the graph is that the graphed function has a greater maximum value.

Learn more about graph here:

brainly.com/question/14323743

#SPJ1

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Ilia_Sergeevich [38]

Answer:

The rate of change of the area of the circle is  approximately -490.09 \ m^2/min.

Step-by-step explanation:

Given:

\frac{dr}{dt} = -6.5 \ m/min

radius r =12 \ m

We need to find the rate of change of the area of the circle at that instant.

Solution:

Now we know that;

Area of the circle is given by π times square of the radius.

framing in equation form we get;

A= \pi r^2

to find the rate of change of the area of the circle at that instant we need to take the derivative on both side.

\frac{dA}{dt}=\frac{d(\pi r^2)}{dt}\\\\\frac{dA}{dt}= 2\pi r \frac{dr}{dt}

Substituting the given values we get;

\frac{dA}{dt}= 2\times \pi \times 12 \times -6.5\\\\\frac{dA}{dt}\approx -490.09 \ m^2/min

Hence The rate of change of the area of the circle is  approximately -490.09 \ m^2/min.

6 0
3 years ago
you have $124 saved in your savings account and your goal for the end of the year is to have at least $300 saved. how much do yo
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Answer:

Step-by-step explanation:

300-124= 176

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<img src="https://tex.z-dn.net/?f=%5Csf%20%5Csqrt%7B12%7D%20%5Ctimes%20%5Csqrt%7B12%7D" id="TexFormula1" title="\sf \sqrt{12} \t
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Answer:

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Step-by-step explanation:

\sqrt{12} \times\sqrt{12}

\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{a}=a,\:\quad \:a\ge 0

\sqrt{12}\sqrt{12}=12

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Wewaii [24]

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Step-by-step explanation:

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3 years ago
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