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vitfil [10]
3 years ago
11

Solve q=w-4/ z for w

Mathematics
1 answer:
Scilla [17]3 years ago
7 0

Answer:

w=qz+4

Step-by-step explanation:

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Estimate to the nearest 0.5 unit and classify the extrema for the graph of each function.
VLD [36.1K]

f(x) = x^3+x^2-x

Finding the extreme point :

f'(x)=3x^2+2x-1=0\\\\3x^2+3x-x-1=0\\\\3x(x+1)-1(x+1)=0\\\\(3x-1)(x+1)=0\\\\x=\dfrac{1}{3}\ ,\ x=-1

Now,

f''( x ) at x = 1/3 and -1 is :

f''(x)=6x+2\\\\f''(1/3)=4  \\\\f''(-1)=-4

Therefore, it is maximum at x = -1 and minimum at x = 1/3 .

Hence, this is the required solution.

3 0
3 years ago
If a concrete column is 6 inches by 6 inches square and 8 ft. long, calculate its weight in Newtons, given a specific weight of
tangare [24]
<h2>Weight of column is 555.83 N</h2>

Step-by-step explanation:

Size of column = 6 inch x 6 inch x 8 ft

Size of column = 0.5 ft x 0.5 ft x 8 ft

Volume of column = 0.5 x 0.5 x 8 = 2 ft³

Specific weight of concrete = 62.4 lb/ft³

Mass = Volume x Specific weight

Mass = 2 x 62.4

Mass = 124.8 lb = 124.8 x 0.454 = 56.66 kg

Weight = 56.66 x 9.81 = 555.83 N

Weight of column is 555.83 N

7 0
3 years ago
How much ₹ each will get if 242.46₹ is distributed equally among the students​
slavikrds [6]

<em>Complete Question:</em>

<em>How much ₹ will each get if 242.46₹ is distributed equally among the 6 students​ </em>

Answer:

Each of the 6 students will get ₹40.41

<em></em>

Step-by-step explanation:

Given

Amount = 242.46

Students = 6

Required

Determine how much each student gets

To do this, we simply divide the total amount by the number of students

i.e.

Each\ Students = \frac{Amount}{Number\ Students}

Each\ Students = \frac{242.46}{6}

Each\ Student = 40.41

<em>Hence, each of the 6 students will get ₹40.41</em>

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3 years ago
Explain how you can determine if 1/3 and 4/12 are equivalent fractions
miv72 [106K]
<span>4/12 = 2/6 = 1/3 is your Answer</span>
7 0
3 years ago
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Sin θ = − 8/17 and θ is in Quadrant III, find tan(θ/2)
yuradex [85]

Answer: 45

Step-by-step explanation:

7 0
3 years ago
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