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Liono4ka [1.6K]
2 years ago
11

A number cube is rolled. What is the probability

Mathematics
1 answer:
cluponka [151]2 years ago
5 0

Step-by-step explanation:

a complicated way to say "the probability to roll a number that is less or equal to 5".

and that is

5 desired cases over 6 total cases, and that means

5/6 = 0.833333333...

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Help me out from 25-32 also show work (Geometry)
astraxan [27]

Answer:

Step-by-step explanation:

25.

x + 2x -75 = 90

3x = 90+75

3x = 165

x = 55

Measure of A = 55

Measure of B = 2(55) - 75 = 110 - 75 = 35

28.

2x+10-x+55 = 90

x = 90-65

x = 25

measure of A = 2(25) +10 = 60

measure of B = -25+55 = 30

31.

2x+3+3x - 223 = 180

5x -220 = 180

5x = 400

x = 80

measure of A = 163

measure of B = 17

32.

-4x+40+x+50 = 180

-3x +90 = 180

-3x = 90

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8 0
3 years ago
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
732,178+167-542,137=
madreJ [45]
( 732,178 + 167 ) = 899,178
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3 years ago
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If the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb, how much work is needed to stretch it 6 in.
mel-nik [20]

Answer:

0.375 feet-lb

Step-by-step explanation:

We have been given that the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb. We are asked to find the work needed to stretch the spring 6 in. beyond its natural length.

We can represent our given information as:

6=\int\limits^2_0 {F(x)} \, dx

We will use Hooke's Law to solve our given problem.

F(x)=kx

Substituting this value in our integral, we will get:

6=\int\limits^2_0 {kx} \, dx

Using power rule, we will get:

6=\left[ \frac{kx^2}{2} \right ]^2_0

6=\frac{k(2)^2}{2}-\frac{k(0)^2}{2}

6=\frac{4k}{2}-0\\\\k=3

We know that 6 inches is equal to 0.5 feet.

Work needed to stretch it beyond 6 inches beyond its natural length would be \int\limits^{0.5}_0 {kx} \, dx =\int\limits^{0.5}_0 {3x} \, dx

Using power rule, we will get:

\int\limits^{0.5}_0 {3x} \, dx = \left [\frac{3x^2}{2}\right]^{0.5}_0

\frac{3(0.5)^2}{2}-\frac{3(0)^2}{2}\Rightarrow \frac{3(0.25)}{2}-0=\frac{0.75}{2}=0.375

Therefore, 0.375 feet-lb work is needed to stretch it 6 in. beyond its natural length.

3 0
3 years ago
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Olenka [21]
The answer is D. 77. This stuff is 2EZ for me
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3 years ago
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