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2 years ago

A number cube is rolled. What is the probability

Mathematics

1 answer:

cluponka [151]2 years ago

5 0

Step-by-step explanation:

a complicated way to say "the probability to roll a number that is less or equal to 5".

and that is

5 desired cases over 6 total cases, and that means

5/6 = 0.833333333...

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Help me out from 25-32 also show work (Geometry)

astraxan [27]

Answer:

Step-by-step explanation:

25.

x + 2x -75 = 90

3x = 90+75

3x = 165

x = 55

Measure of A = 55

Measure of B = 2(55) - 75 = 110 - 75 = 35

28.

2x+10-x+55 = 90

x = 90-65

x = 25

measure of A = 2(25) +10 = 60

measure of B = -25+55 = 30

31.

2x+3+3x - 223 = 180

5x -220 = 180

5x = 400

x = 80

measure of A = 163

measure of B = 17

32.

-4x+40+x+50 = 180

-3x +90 = 180

-3x = 90

x= -30

measure of A = -4(-30) +40 = 160

measure of B = -30+50 = 20

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3 years ago

Help me plssssssssssssssssssssssss

natka813 [3]

Answer:

Step-by-step explanation:

Minus two equations , we got:

9x-9y= 132-(-12)

9x-9y=144

x-y=16

5 0

3 years ago

732,178+167-542,137=

madreJ [45]

( 732,178 + 167 ) = 899,178
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3 years ago

Read 2 more answers

If the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb, how much work is needed to stretch it 6 in.

mel-nik [20]

Answer:

0.375 feet-lb

Step-by-step explanation:

We have been given that the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb. We are asked to find the work needed to stretch the spring 6 in. beyond its natural length.

We can represent our given information as:

$6=\int\limits^2_0 {F(x)} \, dx$

We will use Hooke's Law to solve our given problem.

$F(x)=kx$

Substituting this value in our integral, we will get:

$6=\int\limits^2_0 {kx} \, dx$

Using power rule, we will get:

$6=\left[ \frac{kx^2}{2} \right ]^2_0$

$6=\frac{k(2)^2}{2}-\frac{k(0)^2}{2}$

$6=\frac{4k}{2}-0\\\\k=3$

We know that 6 inches is equal to 0.5 feet.

Work needed to stretch it beyond 6 inches beyond its natural length would be $\int\limits^{0.5}_0 {kx} \, dx =\int\limits^{0.5}_0 {3x} \, dx$

Using power rule, we will get:

$\int\limits^{0.5}_0 {3x} \, dx = \left [\frac{3x^2}{2}\right]^{0.5}_0$

$\frac{3(0.5)^2}{2}-\frac{3(0)^2}{2}\Rightarrow \frac{3(0.25)}{2}-0=\frac{0.75}{2}=0.375$

Therefore, 0.375 feet-lb work is needed to stretch it 6 in. beyond its natural length.

3 0

3 years ago

Evaluate the expression. 7 · (8 + 3) A. 18 B. 29 C. 59 D. 77

Olenka [21]

The answer is D. 77. This stuff is 2EZ for me

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3 years ago

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