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erik [133]
3 years ago
10

What is the measure of

Mathematics
1 answer:
babymother [125]3 years ago
7 0

Answer:

Sub to SZ Lexrn if that does not show search up shiyo on vr and first vid is them please help out , thx bye . If you do it cmt and ill make a post for yall for 100 points

Step-by-step explanation:

You might be interested in
Round 6.071981 to 3 significant figures
natita [175]

Answer:

6.071

Step-by-step explanation:

All non zero numbers are significant irrespective of where decimal point is

If zero is between to numbers it is significant irrespective of where decimal point is

5 0
3 years ago
2y - 4x = 4 Rewrite:
USPshnik [31]

Answer:

y - 2x = 2

Step-by-step explanation:

2y - 4x = 4

2(y - 2x) = 4  | : 2

y - 2x = 2

6 0
3 years ago
Read 2 more answers
If angle 1= 105°, angle 12= (3x + 15)°, and angle 7 = (8y-5)°, determine the values<br> of x and y.
Darina [25.2K]

The value of the variable x is 30° and the value of the variable y is 10°.

The missing diagram is attached below.

<h3>What is an angle?</h3>

The angle is the distance between the intersecting lines or surfaces.

Corresponding angle – If two lines are parallel, then the third line. The corresponding angles are equal angles.

Vertically opposite angle – When two lines intersect, then their opposite angles are equal.

Linear angle – If the total of two angles is 180 degrees, they are said to be linear angles.

∠1 = ∠5 = ∠9 = 105° (corresponding angles)

∠1 = ∠4 = 105° (Vertical opposite angles)

∠1 + ∠2 = 180° (linear angle)

       ∠2 = 75°

∠2 = ∠3 = 75° (Vertical opposite angles)

∠3 = ∠8 = ∠12 = 75° (corresponding angles)

If angle ∠1 = 105°, angle ∠12 = (3x + 15)°, and angle ∠7 = (8y-5)°.

Then the value of x and y will be

   ∠9 = ∠12

   ∠1 = ∠12

105° = (3x + 15)°

  3x = 90°

    x = 30°

∠6 = ∠7

75° = (8y – 5)°

8y = 80°

  y = 10°

More about the angled link is given below.

brainly.com/question/15767203

#SPJ1

7 0
2 years ago
Help math question derivative!
atroni [7]
Let f(x)=\sec^{-1}x. Then \sec f(x)=x, and differentiating both sides with respect to x gives

(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1
f'(x)=\dfrac1{\sec f(x)\tan f(x)}

Now, when x=\sqrt2, you get

(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}

You have \sec^{-1}\sqrt2=\dfrac\pi4, so \sec\left(\sec^{-1}\sqrt2\right)=\sqrt2 and \tan\left(\sec^{-1}\sqrt2\right)=1. So (\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}
5 0
3 years ago
Given the function f(x) = -5|x + 11 + 3, for what values of x is f(x) = -12?
katen-ka-za [31]

Answer: B

Step-by-step explanation:

6 0
2 years ago
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