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Vadim26 [7]
2 years ago
15

A person standing at the top of mountain everest would be approximately 5.5 mi high. the radius of earth is 3959 mi. what is the

distance to the horizon from this point? enter your answer as a decimal in the box. round only your final answer to the nearest tenth.
SAT
1 answer:
poizon [28]2 years ago
6 0

Based on the calculations, the distance to the horizon (H) from this point is equal to 208.8 miles.

<h3>How to calculate the distance to the horizon?</h3>

Based on the diagram attached in the image below, a triangle with the center of planet Earth (C) at one point is formed, with the horizon (H) and the top of Mt. Everest (O) as the other points.

In accordance with Pythagorean theorem, we would set up an equation from the right-angle triangle (CHO) as follows:

d² + r² = (r + h)²

d² + 3959² = (3959 + 5.5)²

d² + 15,673,681 = 3964.5²

d² + 15,673,681 = 15,717,260

d² = 15,717,260 - 15,673,681

d² = 43,579

d = √43,579

Distance, d = 208.8 miles.

Read more on Pythagorean theorem here: brainly.com/question/23200848

#SPJ1

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