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2 years ago

(6+9i)(6-9i) How to solve?

1 answer:

5 0

$~~(6+9i)(6-9i)\\\\=6^2-(9i)^2~~~~~~~~~~~~~~~~~~~;[a^2-b^2 =(a+b)(a-b)]\\\\=36-81i^2\\\\=36-81(-1)~~~~~~~~~~~~~~~~;[i^2 = -1]\\\\=36+81\\\\=117$

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Y=2x+9 what the answer

tekilochka [14]

Answer:

x=Y/2−9/2

Step-by-step explanation:

please mark brainliest :)

8 0

3 years ago

PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM

Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

$c^{2} =a^{2} +b^{2}$

c = $\sqrt{a^{2} +b^{2} }$

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = $\sqrt{40^{2} + 9^{2} }$

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = $\sqrt{12^{2} + 13^{2} }$

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$35^{2} = 20^{2} + b^{2}$

1225 = 400 + $b^{2}$

$b^{2}$ = 1225 - 400

$b^{2}$ = 825

$\sqrt{b^{2} } = \sqrt{825}$

b = 5 $\sqrt{33}$

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$37^{2} = 20^{2} + b^{2}$

1369 = 400 + $b^{2}$

$b^{2}$ = 1369 - 400

$b^{2}$ = 969

Taking square root on both sides

b = 31.12

Hope it helps.

4 0

2 years ago

Okay how do I reach out to Katie. I'm gonna scream-. I have stopped answering questions for this reason and they still delete my

Vesna [10]

Answer:

You can't she do the same thing to me like I just be answering question for points and they mostly be correct and she just be deleting the questions like crazy.

3 0

2 years ago

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netineya [11]

Answer:

x - 5

Step-by-step explanation:

$((x - 5) {}^{ \frac{3}{2} } ) {}^{ \frac{2}{3} }$

$(x - 5) {}^{ \frac{3}{2} } { \times }^{ \frac{2}{3} }$

$(x - 5) {}^{ \frac{6}{6} }$

$(x - 5) {}^{1}$

Therefore x - 5

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2 years ago

A group of students is collecting books to add to their

pentagon [3]

Answer:(2,23) & (7,48)

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers