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shtirl [24]
2 years ago
5

Ben bowled 160 and 191 in his first two games. What must he bowl in his third game to have an average of at least 190?​

Mathematics
1 answer:
natita [175]2 years ago
7 0
I don’t understand the question
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A game of chance is begun. You will pick one number out of 300. If your number is picked you win $30,000. At what point is it no
garik1379 [7]

Answer:

<$100 / greater than $100

Step-by-step explanation:

30,000/300=100

If you spent $100 per spin and won 1 out of 300 games, there would be no net gain.

If you spent anything more than $100, then you would lose more money than you gained if you won 1 out of 300 games.

3 0
3 years ago
Which values of x are point(s) of discontinuity for this function? Function x = –4 x = –2 x = 0 x = 2 x = 4
Nadya [2.5K]

Answer:

the answer is x=0 and x=2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Fowle Marketing Research Inc., bases charges to a client on the assumption that telephone surveys can be completed in a mean tim
sergejj [24]

Answer:

a) Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

b) t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958      

c) p_v =P(t_{34}>2.958)=0.0028    

d) If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

The sample mean is given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And the sample deviation is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=17 represent the sample mean    

s=4 represent the sample standard deviation

n=35 sample size  

\mu_o =15 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less or equal than 15, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

Since we don't  know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958  

Part c P-value  

The degrees of freedom are given by:

df = n-1= 35-1=34

Since is a right tailed test the p value would be:  

p_v =P(t_{34}>2.958)=0.0028  

Part d Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.  

7 0
3 years ago
Зу+9=14
Anon25 [30]

Answer:

Constant(s) = 14,9

Coefficient = 3

Variable = y

6 0
3 years ago
What is the equation of the line that passes through the point (-5,5) and has a slope of -1
max2010maxim [7]

Answer:

y - 5 = -(x + 5)

y - 5 = -x - 5

y = -x

7 0
4 years ago
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