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2 years ago

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Point A is at-4 and point B is at 6. Which describes one way to find the point that divides AB into a 3:2 ratio?

1 answer:

galben [10]2 years ago

7 0

The point that divides AB into a 3:2 ratio is calculated by (d) for a ratio of 3:2, divide AB into 5 equal parts. Each equal part is 2 units, so the point that divides AB into a 3:2 ratio is 2

<h3>How to determine the ratio?</h3>

The given parameters are:

A = -4

B = 6

Start by calculating the length AB using:

AB = |B - A|

This gives

AB = |6 -(-4)|

Evaluate

AB = 10

Next, the length is divided into 5 parts.

So, the length of each part is:

Length = 10/5

Length = 2

The point on the location 3 : 2 is then calculated as:

Point = A + 3 * Length

This gives

Point = -4 + 3 * 2

Evaluate

Point = 2

The above computation is represented by option (d)

Read more about number lines at:

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You buy 3 tickets for $48 total for the jazz concert on

statuscvo [17]

Answer: Friday night. Least expensive ticket

Step-by-step explanation:

Friday night.: 48/3 =16 so each ticket costs $16

Saturday night 36/2= 18 so each ticket costs $18

Brother collects 96/6 = 16. So each person had enough for a $16 ticket. They can go to the Friday night concert. They paid for the least expensive ticket.

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4 years ago

A train ticket to the city centre costs £2.85.

Ivanshal [37]

Answer:

£74.10 is the total cost for 26 tickets

Step-by-step explanation:

£2.85 for 1 ticket.

For 26 tickets:

2.85 × 26 = £74.10

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4 years ago

Read 2 more answers

Please help! Will give brainliest!

const2013 [10]

<h3>1.</h3>

The equation in point-slope form: y - y₁ = m(x - x₁)

slope: m = -2

point: (4, -5) ⇒ x₁ = 4, y₁ = -5

Therefore, the equation of the line in point-slope form:

<h3>y + 5 = -2(x - 4)</h3>

<h3>2.</h3>

The equation in slope-intercept form: y = mx + b

Parallel lines has the same slope, so:

y = 4x + 2 ⇒ a = 4

If a line passes through the point <em>(x₁, y₁) </em>then the equation y<em>₁</em> = mx<em>₁</em> + b is true.

(4, 6) ⇒ x₁ = 4, y₁ = 6

So: 6 = 4·4 + b ⇒ b = -10

Therefore the equation:

<h3>y = 4x - 10</h3>

<h3>3.</h3>

a = 3

(-1, 1) ⇒ x₁ = -1, y₁ = 1

So: 1 = 3·(-1) + b ⇒ b = 4

The equation:

<h3>y = 3x + 4</h3>

<h3>4. </h3>

The product of slopes of perpendicular lines is -1.

2x - 7y = 1 ⇒ 7y = -2x + 1 ⇒ y = -²/₇x + ¹/₇

-²/₇×m = -1 ⇒ m = ⁷/₂

(0, -4) ⇒ x₁ = 0, y₁ = -4

-4 = ⁷/₂·0 + b ⇒ b = -4

The equation:

<h3>y = ⁷/₂x - 4</h3>

8 0

3 years ago

ASAP PLEASE ANSWER quadrilateral ABCD is dilated at center (0,0) with scale factor 1/2 to form quadrilateral A'B'C'D'. wha is th

zhenek [66]

Answer:

$|A'B'|=\sqrt{5}$

Step-by-step explanation:

The points A and B have coordinates at (0,4) and (4,2) respectively.

The distance formula can be used to find the length of AB.

$|AB|=\sqrt{(4-0)^2+(2-4)^2}$

$|AB|=\sqrt{(4)^2+(-2)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

$|AB|=2\sqrt{5}$

Since quadrilateral ABCD was enlarged with a scale factor of $\frac{1}{2}$ .

The length of A'B' is

$\frac{1}{2}|AB|$

$=\frac{1}{2}\times2\sqrt{5}$

$\therefore |A'B'|=\sqrt{5}$

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3 years ago

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anygoal [31]

Answer:

D. (3p, 3p + 4)

Step-by-step explanation:

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3 years ago