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3 years ago

A battery manufacturer randomly tests 500 batteries and finds that 3 are defective.

1 answer:

5 0

To find this answer, we must first find the percentage of batteries that are defective. We can do this by dividing 3 by 500.

3 / 500 = 0.006

So our percentage of defective batteries is 0.6%.

Now, to find out how many defective batteries would be in a batch of 12000, we just need to multiply the constant (percentage of defective batteries) by the amount in the new batch.

12000 * 0.006 = 72

In a shipment of 12,000 batteries, 72 will be defective, so the correct answer choice would be B.
Hope that helped =)

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Step-by-step explanation:

let the denominator of the original fraction be x, then

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After the given changes, that is

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6x - 42 = 3x + 48 ( subtract 3x from both sides )

3x - 42 = 48 ( add 42 to both sides )

3x = 90 ( divide both sides by 3 )

x = 30

Thus

$\frac{30-7}{30}$ = $\frac{23}{30}$ ← the original rational number

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