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natima [27]
3 years ago
13

Alike & Different

Mathematics
1 answer:
nekit [7.7K]3 years ago
7 0

Answer: Don't know sorry

Step-by-step explanation:

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Round 1289.48 to the nearest dollar please
Ilya [14]
$1290 or you could use 1289.50
8 0
4 years ago
Read 2 more answers
3^2 - 2x + 4 and g(x) = 5x^2 + 6x - 8 find f-g(x)
sveta [45]

Answer:

For the given functions f(x) and g(x) (f-g)(x) = -2x^{2}  - 8x +12

Step-by-step explanation:

Here, the given function are:

f(x)  = 3x^{2}  - 2x+ 4\\g(x) = 5x^{2}  + 6x -8

Now, simplifying for (f-g)(x)  =  f(x) -  g(x):

f(x) - g(x)  = (3x^{2}  - 2x+ 4) - (5x^{2}  + 6x -8)

 = 3x^{2}  - 2x+ 4- 5x^{2}  - 6x +8

Doing operation on LIKE TERMS,  we get

f(x) -  g(x) = ( 3x^{2}- 5x^{2})   + (-2x - 6x)  +( 4 +8) = -2x^{2}  - 8x + 12

Hence, for the given functions f(x) and g(x) (f-g)(x) = -2x^{2}  - 8x +12

4 0
3 years ago
F(x) = 3x -6 What is 7 times f(x)​
Alina [70]

Answer:

21x - 42, see below :)

Step-by-step explanation:

Hello!

We know that f(x) is equal to 3x - 6

We want to know what 7 * f(x) is so we should first substitute f(x) for 3x - 6

7 * f(x)

7(3x-6)

We use distributive property to open the parenthesis:

7 * 3x + 7 * -6

21x - 42

8 0
3 years ago
Read 2 more answers
The graph shows the relationship between the number of months different students practiced baseball and the number of games they
ratelena [41]

Answer:

A) from the line of best fit, the approximately y-intercept is (0,1.8). This means without any practice, 1h.8 games are won.

B) slope: (5.6-1.8)/(2-0) = 1.9

y = 1.9x + 1.8

(Line of best fit)

x = 13,

y = 1.9(13) + 1.8 = 26.5

Predicted no. of games won after 13 months of practice is 26.5

7 0
3 years ago
Read 2 more answers
A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t
MakcuM [25]

Answer:

165.

Step-by-step explanation:

Since repetition isn't allowed, there would be 11 choices for the first donut, (11 - 1) = 10 choices for the second donut, and (11 - 2) = 9 choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 11 \times 10 \times 9 unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 3 \times 2 \times 1 = 6 times.

For example, if a bag includes donut of type x, y, and z, the count 11 \times 10 \times 9 would include the following 3 \times 2 \times 1 arrangements:

  • xyz.
  • xzy.
  • yxz.
  • yzx.
  • zxy.
  • zyx.

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count 11 \times 10 \times 9 by 3 \times 2 \times 1 = 6 to find the actual number of donut combinations:

\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 3 objects from a set of 11 distinct objects:

\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

5 0
2 years ago
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