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Marizza181 [45]
3 years ago
14

What are the points of discontinuity? Are they all removable? Please show your work.

Mathematics
1 answer:
Nastasia [14]3 years ago
6 0
For this case we have the following expression:
 y = (x-5) / (x ^ 2 - 6x +5)
 Rewriting the expression we have:
 y = (x-5) / ((x-5) (x-1))
 Therefore, discontinuity points are those that make the denominator zero:
 x = 5
 x = 1
 The point of removable discontinuity is:
 x = 5
 Answer:
 
Discontinuity:
 
x = 5
 
x = 1
 
Removable:
 
x = 5
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5.6 by the power of negative 5 can someone tell me what that equals <br><br> PLZ HELP NOW
dmitriy555 [2]
0.00018157659
hope this helps you
8 0
2 years ago
Read 2 more answers
An animal shelter has a 58% adoption rate for puppies. Of all puppies in the shelter, 80% live to be 7 years or older. Of the pu
dexar [7]

Answer:

P(A∩B) = 0.522

Step-by-step explanation:

Let's call A the event that a puppy is adopted and B the probability that a puppy live 7 or more years

So, the probability P(A∩B) that a randomly selected puppy in the shelter will get adopted and live 7 or more years is:

P(A∩B) = P(A)*P(B/A)

Because A and B are not independents.

Then, the probability P(A) that a puppy is adopted is 58% and the probability P(B/A) that a puppy live 7 or more years given that the puppy is adopted is 90%.

Finally, replacing the values, we get:

P(A∩B) = 0.58*0.9 = 0.522

It means that the 52.2% of the puppies are adopted and live 7 or more years.

7 0
3 years ago
Which table describes the behavior of the graph of f(x) = 2x3 – 26x – 24?
In-s [12.5K]

Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

Step-by-step explanation:

f(x)=2x^{3}-26x-24

2x^{3}-26x-24=0

2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\

=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\

=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis



7 0
3 years ago
Read 2 more answers
1
ankoles [38]
We subtract the 17 from the 981 to make the two sides even so it’s easier to calculate, 981 - 17 = 964, then divide that by 2, 964/2 = 482. So your answer is 482.

Would appreciate brainliest!
6 0
2 years ago
Solve the equation <br> 3= x/6 + 1
dangina [55]

Answer:

x = 12

Step-by-step explanation:

7 0
2 years ago
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