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Vikentia [17]
3 years ago
6

Dz where y is a circle of radius 2 and center 0 Exercise 1. Evaluate 1 +z2

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0

Answer:

-21

Step-by-step explanation:

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Give the intervals where f(x) is concave up. (enter your answer using interval notation. if an answer does not exist, enter dn
Kipish [7]
Concave up is U-shaped.
There will be a inflection/critical point f'(x) =0 then a negative slope f'(x) = neg then another inflection/critical point f'(x) =0 at the bottom of the U-shape then a positive slope to last inflection/critical point. The interval for the Concave Up shape is the first and last inflection points.
6 0
3 years ago
Helppppppppppppppp pleaseeeeee!
stepan [7]

Answer and Explanation:

You got the first one right!

2. You do the same as you did for the first one: to combine the exponents, you multiple 2 by 9 = 18, and now 18 is your new exponent.

3^{2*9} = 3^{18} , which is the answer

3. Here, you can split up the inside so that you have:

2^5*(y^2)^5= 32*y^{2*5}=32y^{10} , which is the answer

Hope this helps! Please give me brainliest if possible.

3 0
3 years ago
Read 2 more answers
Please help asap I genuinely cannot figure this out
Gemiola [76]

Answer:

C

Step-by-step explanation:

We can use the factored form of the quadratic equation, given by:

y=a(x-p)(x-q)

Where <em>a</em> is the leading coefficient and <em>p</em> and <em>q</em> are the zeros.

We have zeros <em>x</em> = -2 and <em>x</em> = 3. So, let <em>p</em> = -2 and <em>q</em> = 3:

y=a(x+2)(x-3)

Next, we are given that our <em>y-</em>intercept is (0, -30).

In other words, when <em>x</em> = 0, <em>y</em> = -30. So:

-30=a(0+2)(0-3)

Solve for <em>a:</em>

<em />-30=-6a\Rightarrow a=5<em />

<em />

Hence, our factored equation is:

\displaystyle y=5(x+2)(x-3)

For the standard form, expand:

y=5(x^2-3x+2x-6)

Simplify:

y=5(x^2-x-6)

Distribute:

y=5x^2-5x-30

Our answer is C.

4 0
3 years ago
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Dave's age in 4 years is 18. Write an equation that represents Dave's age in 4 years.
julsineya [31]
This equation might be x + 4 =18

3 0
3 years ago
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What is an equation of the line that passes through (-2,3) and (6,-1)?
erica [24]

Answer:

Step-by-step explanation:

Slope = (-1-3)/(6+2) = -4/8 = -1/2

Equation of a line is

y-y1 = m(x-x1)

y-3 = (-1/2)(x+2)

y = 3 + (-1/2)(x+2)

3 0
2 years ago
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