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Ivanshal [37]
1 year ago
10

Factoring a quadratic with leading coefficient greater than 1 3n^2+5n+2=0

Mathematics
1 answer:
Alika [10]1 year ago
8 0

The algebraic factor is the multiplication term that can be common to the whole equation thus the factorization form of 3n²+5n+2=0 will be (n + 1)(3n + 2) = 0.

<h3>What is an algebraic factor?</h3>

An algebraic factor is the multiplication of two algebraic terms.

The root of the quadratic equation formed by the algebraic factor is always real.

That term could be in form of summation multiplication or in subtraction.

As per the given quadratic equation,

3n²+5n+2=0

Let's 5n = 2n + 3n

3n²+ (3n + 2n) + 2 = 0

3n² + 3n + 2n + 2 = 0

(3n² + 3n) + (2n + 2) = 0

3n(n + 1) + 2(n + 1) = 0

(n + 1 )(3n + 2) = 0

Hence "The algebraic factor is the multiplication term that can be common to the whole equation thus the factorization form of 3n²+5n+2=0 will be (n + 1)(3n + 2) = 0".

For more about the algebraic factor,

brainly.com/question/19426180

#SPJ1

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kirza4 [7]

Answer: x=18(27)+172

Step-by-step explanation:

You have the following information given in the problem:

- The number of soccer fans that are going to a soccer game is 27.

- A ticket to the game costs $18 per person.

- The cost of the lunch for all 27 fans is $172.

- x represents the total cost of attending the game for all 27 fans.

Therefore, keeping the above on mind you can write the following expression that closely estimates the total cost of attending the game for all 27 fans:

x=18(27)+172

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What is 25% of 80?<br><br> ( show how u did it cause I have to write it down
Wewaii [24]

Answer:

20

Step-by-step explanation:

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A researcher records the repair cost for 8 randomly selected washers. A sample mean of $60.46 and standard deviation of $18.36 a
Anuta_ua [19.1K]

Answer:

The critical value is T = 1.895.

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 6

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.895, which is the critical value.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.895\frac{18.36}{\sqrt{8}} = 12.301

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159

The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

8 0
3 years ago
A family eats at a restaurant. The bill is $42. The family leaves a tip and spends $49.77.
jeka94

Answer;

7.77

Step-by-step explanation:

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2 years ago
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