Answer:
a)
b)
c)
But we see that the distribution is defined ust between 49.62 and 50.04
And in order to find this we can use the CDF (Cumulative distribution function) given by:

And if we replace we got:

And makes sense since all the values are between 49.62 and 50.04
Step-by-step explanation:
For this case we define the random variable X ="net weigth in pounds of a packaged chemical herbicide" and the distribution for X is given by:

Part a
For the uniform distribution the expected value is given by
where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:
Part b
The variance for an uniform distribution is given by:
And if we replace we got:
Part c
For this case we want to find this probability:
But we see that the distribution is defined ust between 49.62 and 50.04
And in order to find this we can use the CDF (Cumulative distribution function) given by:

And if we replace we got:

And makes sense since all the values are between 49.62 and 50.04
Answer:
me either. I think u have to solve it using the ordered pairs.
Step-by-step explanation:
I think what u would do is multiply the forth thing by 2 and then count how many blocks are in the 5th :)))
0.00067
You always want the period to the right of the first number meaning you’ll start from there counting backwards because it is negative.
Step-by-step explanation:
A) 45
B) 6
C) 6.7082039326