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2 years ago

Diego is solving this system of equations:

Mathematics

1 answer:

USPshnik [31]2 years ago

7 0

The solutions of the equations are x = 1 and y = 2

The system of equations are

4x + 3y = 10

-4x + 5y = 6

Here we have to use the elimination method. Eliminate the x term and find the value of y term

Add both equation

3y + 5y = 10 +6

Add the like terms

8y = 16

y = 16 / 8

Divide the terms

y = 2

Substitute the value of x in the first equation

4x + 3y = 10

4x + 3×2 = 10

Multiply the terms

4x + 6 = 10

4x = 10 - 6

4x = 4

x = 4 / 4

Divide the terms

x = 1

Hence, the solutions of the equations are x = 1 and y = 2

Learn more about elimination method here

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A regular octagon has side lengths of 9 units. Each side of the octagon is

nirvana33 [79]

Answer:

The perimeter of the original octagon is:

72 units.

The perimeter of the new octagon is:

288 units.

Step-by-step explanation:

When it is mentioned that an octagon is regular, it means that all its sides are equal, therefore, each side of the original octagon has a length of 9 units, considering the formula of the octagon's perimeter:

Perimeter of an octagon = 8 * length.

By replacing you get:

Perimeter of the original octagon = 8 * 9 = 72 units.

For the new octagon, it is mentioned that each side increases by 27 units, therefore:

New length = 27 + 9 = 36 units.

Applying the formula of perimeter of an octagon with the new values we obtain:

Perimeter of the new octagon = 8 * 36 = 288 units.

3 0

3 years ago

1 . a sequence in which a fixed amount is added on to get the next term arithmetic sequence 2 . an individual quantity or number

Dmitry [639]

$T_n = a_1 + d(n-1)$

If a = 4 and d = 3,

$T_n = 4+ 3(n-1)$

$T_n = 4+ 3n-3$

$T_n = 3n + 1$

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Answer: The general equation for the nth term is 3n + 1.
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6 0

3 years ago

Find the quotient: 8,358 ÷ 27 = ________. 309 r 15 309 r 26 310 r 15 310 r 26

Rus_ich [418]

Answer:

the answer is 309 r 15

Step-by-step explanation:

309 × 27 is 8343 and your left with 15

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3 years ago

Consider the following hypothesis test: H 0: 20 H a: < 20 A sample of 60 provided a sample mean of 19.5. The population stand

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