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serg [7]
2 years ago
5

3) show that the two lines with the given slopes are parallel, perpendicular neither. My₁ = 3/4 M₂ = 12/16 . solve it by showing

step by step​
Mathematics
2 answers:
Jet001 [13]2 years ago
8 0

Parallel lines have equal slope so

  • M1-M2=0

Lets check

  • M1=3/4
  • M2=12/16=3/4

Now

  • M1-M2
  • 3/4-3/4
  • 0

Lines are parallel

salantis [7]2 years ago
3 0

Answer:

The two lines are <u>parallel</u>

Step-by-step explanation:

If two lines are <u>parallel</u>, they have the <u>same slope</u>.

If two lines are <u>perpendicular</u>, the slopes will be <u>negative reciprocals</u> (the product of the slopes will be -1).

Given slopes:

\sf m_1=\dfrac{3}{4}

\sf m_2=\dfrac{12}{16}

Reduce m₂ to its simplest form by dividing the numerator and denominator by the largest common factor:

\sf m_2=\dfrac{12 \div 4}{16\div 4}=\dfrac{3}{4}

Therefore,

\sf as \quad \dfrac{3}{4}=\dfrac{3}{4} \implies m_1=m_2 \quad

As the given slopes are the <u>same</u>, the two lines are <u>parallel</u>.

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The sum of the second and third terms of a geometric progression is six times the fourth term.
Luba_88 [7]

Step-by-step explanation:

a2 = a1×r

a3 = a1×r²

a1×r + a1×r² = 6×a4 = 6×a1×r³

1.

r + r² = 6r³

6r³ - r² - r = 0

r×(6r² - r - 1) = 0

the first solution is obvious : r = 0.

but this is no useful ratio for a geometric sequence.

the other 2 solutions are in

6r² - r - 1 = 0

the general solutions for a quadratic equation are

(-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 6

b = -1

c = -1

so,

(1 ± sqrt(1 - 4×6×-1))/12

r = (1 ± sqrt(25))/12

r = (1 ± 5)/12

r1 = (1+5)/12 = 6/12 = 1/2

r2 = (1-5)/12 = -4/12 = -1/3

2.

we can ignore r2 (negative) and just focus on r1 (1/2).

the second term is 8. that means

a2 = 8 = a1×r = a1×1/2

a1 = 2×a2 = 16

so, we have

a1 = 16

a2 = 8

a3 = a2×1/2 = 8×1/2 = 4

a4 = a3×1/2 = 4×1/2 = 2

a5 = a4×1/2 = 2×1/2 = 1

a6 = a5×1/2 = 1×1/2 = 1/2

a7 = a6×1/2 = 1/2 × 1/2 = 1/4

6 0
3 years ago
I’ll give brainley and 10 points
Licemer1 [7]

Answer:At a charity fund raiser , adult tickets were sold for 8$ children each and children’s tickets were sold at 2$ each. write an algebraic expression for the total amount raised from the sale of tickets. At a charity fund raiser , adult tickets were sold for 8$ children each and children’s tickets were sold at 2$ each. write an algebraic expression for the total amount raised from the sale of tickets. How much money was raised if the fundraiser sold 238 adult tickets and 375 children’s tickets?

Step-by-step explanation:

2,654$

Step-by-step explanation:

8a + 2c

8 x 238 = 1,904

2 x 375 =  750

750 + 1,904 = 2,654

2,654$

5 0
3 years ago
Pens are sold in packs of 3 for $5. Pencils are sold in packs of 4 for $1. Mr. James bought 9 pens and 4 pencils and also spent
Brums [2.3K]

Answer:

C.(3 × $5) + $1 + $3 = x

Step-by-step explanation:

3x9=15($15 for pens)

$1 for pencils

$3 (for paper)

so (3 × $5) + $1 + $3 = x

hope this helps! C:

7 0
3 years ago
The sum of 15 and n is less than or equal to 8.
lyudmila [28]

Answer:

n ≤ -7

Step-by-step explanation:

Sum of 15 and n is less than or equal to 8.

15 + n ≤ 8

Collect like terms

n ≤ 8 – 15

n ≤ -7

8 0
3 years ago
Mark draws a card 50 times from a standard deck of 52 cards and gets a Heart 8 times. What is the experimental probability that
Inessa [10]
<span>Experimental probability is defined as the ratio of the number of times an event occurs to the total number of trials the activity is performed

In this case the number that the event occurred is 8 and the number of trials is 50, so the ratio is 8/50 = 4/25.

Then the answer is option B: 4/25
</span>
4 0
3 years ago
Read 2 more answers
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