Question

3) show that the two lines with the given slopes are parallel, perpendicular neither. My₁ = 3/4 M₂ = 12/16 . solve it by showing step by step​

Answer 1

Parallel lines have equal slope so

• M1-M2=0

Lets check

• M1=3/4
• M2=12/16=3/4

Now

• M1-M2
• 3/4-3/4
• 0

Lines are parallel

Answer 2

Answer:

The two lines are parallel

Step-by-step explanation:

If two lines are parallel, they have the same slope.

If two lines are perpendicular, the slopes will be negative reciprocals (the product of the slopes will be -1).

Given slopes:

$\sf m_1=\dfrac{3}{4}$

$\sf m_2=\dfrac{12}{16}$

Reduce m₂ to its simplest form by dividing the numerator and denominator by the largest common factor:

$\sf m_2=\dfrac{12 \div 4}{16\div 4}=\dfrac{3}{4}$

Therefore,

$\sf as \quad \dfrac{3}{4}=\dfrac{3}{4} \implies m_1=m_2 \quad$

As the given slopes are the same, the two lines are parallel.