The correct answer is: A checkpoint will be activated if the spindle does not attach to a kinetochore.
Prokaryotes, do not undergo mitosis (like eukaryotes) and therefore have no need for a mitotic spindle. Prokaryotes also don’ t have checkpoints foor the regulation of cell division.
Normal eukaryotic cells (unlike cancer cells), move through the cell cycle in a regulated way in order to make sure that cells don't divide under conditions that are unfavorable for them. Information about their own internal state (nutrients, signal molecules, DNA integrity) is signal to go or not to go through the cell division. Because of that there are few checkpoints in the cell cycle at which the cell examines the signals and makes a “decision”. The major checkpoints are:
• The G1- the first point at which it must choose, once it passes the G1 checkpoint the cell enters S phase
• The G2-the cell checks DNA integrity and checks if replication is done well.
• The spindle checkpoint-at the transition from metaphase to anaphase.
<span>Of course feeling like you are going to die is probably the most important priority. Although a heavy weight on your chest can be a dangerous and critical symptom, it still is not as critical as feeling like you are going to die.</span>
Answer:
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<em><u>Every genotypic combination with DD or Dd is classified as Rh Positive (red).</u></em></h3>
Explanation:
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It may be because extra blood rushes to the skin's surface to fight off irritants and encourage healing. Your skin can also become red from exertion, such as after a heart-pounding exercise session.</em></u></h3><h3><u><em>
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This is just an explanation of why there skin might turn red.</em></h3><h3 /><h3>
<u>Hope this helps! </u></h3>
a) Evolutionary fitness can be characterized as a person's commitment to the cutting edge's quality pool,which is chiefly founded on the aggregate or the genotype of the individual.This principally identifies with the conceptive achievement of an organic entity.
It is fundamentally determined by the offspring that can endure and pass on the characteristics/traits.
b) Graph is already uploaded in the below attached document.
c) The population 3 will have the most elevated frequency of heterozygotes,45% of the complete population.
d) Since population 2 is as of now having a low number of heterozygotes, the occasion would totally eliminate them from the population or decreases their number
Explanation:
Frequency of animals in population 1 having both alleles 1 and 3
frequency of allele 1 =0.60
frequency of allele 3= 0.25
Frequency of both allele 1 and 3 would be allele 1 + allele 3 frequency x 100
= 0.60+0.25 X 100= 85%
Lignite. It’s a formation of coal.
