Answer:
2. <em>A reference of type A can be treated as a reference of type B</em> - False
Base class or its objects are not related to their derived class (or its objects).
Explanation:
class A {
int a;
public A() {
a = 7;
}
}
class B extends A {
int b;
public B() {
b = 8;
}
}
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1. <em>After the constructor for class B executes, the variable a will have the value 7 </em>- True.
When an object of a derived class is declared, the constructor of base class is called before the constructor of derived class (is called).
3. <em>Both variables a and b are instance variables </em>- True.
Classes can have instance, or member, variables and methods.
4.<em> After the constructor for class B executes, the variable b will have the value 8</em> - True.
When object of class B is declared, its constructor was called, which initialized variable b to 8.
Answer:
There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:
Let a,b be two numbers.
c=a+b;
print(c);
But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:
Let a be the variable where the input numbers are stored.
while(f==1)
{
printf(“Enter number”);
scanf(“Take number into the variable a”);
sum=sum+a;
printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);
scanf(“Take the input into the variable f”);
}
print(Sum)
Explanation:
hi there answer is given mar me as brainliest
The answer is spreadsheet. I just did this lesson and I got all of the answers right so I know it's correct.
Answer:
A, system software
Explanation:
that is answer an interpreter is a type of system software
A string is generally considered as a data type and is often implemented as an array data structure of bytes (or words) that stores a sequence of elements, typically characters, using some character encoding. String may also denote more general arrays or other sequence (or list) data types and structures.
