2 years ago

Given angle A, how can you construct an angle whose measure is 1/4 of angle A

1 answer:

4 0

Answer: Construct the bisector of angle A, then construct the bisector of one of the angles formed by the original bisector.

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Zolol [24]

Answer:

Step-by-step explanation:

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3 years ago

Rina8888 [55]

Use the Pythagorean theorem:

$a^2+b^2=c^2$

c - a hypotenuse

a, b - legs

We have: a = 9 and c = 12. Substitute:

$9^2+b^2=12^2$

$81+b^2=144$ <em>subtract 81 from both sides</em>

$b^2=63\to b=\sqrt{63}\\\\b=\sqrt{9\cdot7}\\\\b=\sqrt9\cdot\sqrt7\\\\ \boxed{b=3\sqrt{7}}$

A Pythagorean triple consists of three positive integers a, b and c, such that

$a^2+b^2=c^2$ .

$b=3\sqrt{7}$ is not positive integer.

<h3>The sides of the triangle do not form a pythagorean triple.</h3>

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4 years ago

Arte-miy333 [17]

Answer:Please include images of the graphs!

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3 years ago

lbvjy [14]

About one standard ruler is the ESTIMATED length of a piece of paper.

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3 years ago

Free_Kalibri [48]

The answer to that question is 62x ()//‘’::;;

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3 years ago