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Jet001 [13]
4 years ago
5

Round 919827 to the nearst thousand

Mathematics
2 answers:
blondinia [14]4 years ago
5 0
It would be 0 because 8 is over 5 so ya
Anestetic [448]4 years ago
5 0

Answer:

919,827.000

Step-by-step explanation:

You basically just move three places forward from the last number which is 7.

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4 SPARSE BAYESIAN LEARNING
Scorpion4ik [409]

Answer:

Answer:

WF=34

Step-by-step explanation:

Point I lies between points W and F.

It means point WI + IF = WF

SO WI + IF = WF

=

WF = 15x – 21

WI= 7x-3

IF= 2x+4

WI + IF = WF

7x-3 +2x+4= 15X-21

7x+2x-15x= -21-4+3

-6x = -22

X= -22/6

X= 11/3

So WF = 15x – 21

WI= 7x-3

IF= 2x+4

WI + IF = WF

=

7X-3 +2x+4= 15x-21

7x+2x-15x= -21-4+3

-6x = -22

X= -22/6

X= 11/3

So WF = 15x – 21

WF= 15(11/3) -21

WF= 55-21

WF=34

7 0
3 years ago
2 1/4 cups = how many pints
Aleks [24]

Answer:

1 1/8 or 1.125 pints

explanation:

Hope this helps:)

6 0
3 years ago
Please this is my last problem and all my points just solve this for im begging
zheka24 [161]

Answer:

72.54

Step-by-step explanation:

Use formula for trapezoid: a+b/2 * h

5 0
3 years ago
Read 2 more answers
What is the value of x?<br><br> Enter your answer in the box.<br><br> x =
antoniya [11.8K]

Answer:

It's answer is 8

Step-by-step explanation:

hypotenuse (h) = 10

base (b) = 6

perpendicular (p) = x = ?

We know by using Pythagoras theorem

p = √ h² - b²

= √ 10² - 6²

= √ 100 - 36

= √ 64

x = 8

Hope it will help : ) ❤

3 0
3 years ago
Write the equation of a line Parallel to the given line and passes through points (-4, -3); (2, 3). Hints find the slope by usin
julia-pushkina [17]

First, we obtain the gradient (slope) of the first parallel line

\text{gradient, m}_1\text{ = }\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{3-(-3)}{2-(-4)}=\frac{6}{6}\text{ = 1}

Recall that since both lines are parallel, we have that,

m_1=m_2

Thus

m_2\text{ = 1}

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)

Using

\begin{gathered} y\text{ = mx + c} \\ \text{where m = m}_2\text{ = 1} \\ \text{and x = -4 ,  y = -3, we have} \\ -3\text{ = 1(-4) + c} \\ -3\text{ = -4 + c} \\ 4\text{ - 3 = c} \\ c\text{ = 1} \\ \text{Thus, the equation of the line is y = (1)x + 1} \\ y\text{ = x + 1} \end{gathered}

5 0
1 year ago
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