Answer:
I hope it will help you...
Answer:
y = (2/3)x - 3
Step-by-step explanation:
Slope-intercept form: y = mx + b
Note that:
y = (x , y)
m = slope
x = (x , y)
b = y-intercept.
The point is given to you. Note that:
(x , y) = (0 , -3) ∴
x = 0
y = -3
The slope = m = 2/3
Plug in the corresponding numbers to the corresponding variable:
y = mx + b
-3 = (2/3)(0) + b
-3 = 0 + b
b = -3
Plug in -3 for b in the equation:
y = mx + b
y = (2/3)x -3
y = (2/3)x - 3 is your equation.
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Thank you sm! Happy December 1st! Mark b please?
Answer:
Step-by-step explanation:
3b⁵ + 15b⁴ - 18b⁷ = 3b⁵ + [3*5*b⁴] - [6*3*b⁷]
=3b⁴*( b + 5 - 6b³)
Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
