The answer is 36/49.
You take the second fraction and flip it (it will be 12/14) and you multiply straight across. You get 72/98. You simplify it by finding it's greatest common factor (in this case it is 2) so you divide it the numerator and the denominator by 2. You get 36/49.
For this case, the first thing we must do is define variables.
We have then:
n: number of cans that each student must bring
We know that:
The teacher will bring 5 cans
There are 20 students in the class
At least 105 cans must be brought, but no more than 205 cans
Therefore the inequation of the problem is given by:
Answer:
105 <u><</u> 20n + 5 <u><</u> 205
the possible numbers n of cans that each student should bring in is:
105 <u><</u> 20n + 5 <u><</u> 205
<span>A plane is a flat surface that extends infinitely in all directions; thus, a lot of points can be found on a given plane. The plane can be named by taking any three points on it, in no specific order, as long as these points are not on a straight line. An example is plane ABC, given that points A, B and C are found on the plane and are not collinear.</span>
AC and DB are the same length. Set the two to equal each other and solve for y.
9y + 1 = 8y +17
Subtract 8y from both sides:
y + 1 = 17
Subtract 1 from each side:
y = 16
Now you know Y you can find the the length of DB:
DB = 8y +17 = 8(16) +17 = 128 + 17 = 145
EB is half of DB:
EB = 145 / 2
EB = 72.5