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saw5 [17]
2 years ago
14

In a forest ecosystem, skunks eat mice, while coyotes eat both mice and skunks. do these two facts provide enough evidence to pr

edict what will happen to the coyote population if the skunks all die?
a
yes; with the skunks gone, there will be too few mice, and the coyote population will decrease.

b
no; with the skunks gone, there will be many more mice, but this does not affect the coyote population.

c
. yes; with the skunks gone, there will be many more mice, and they will chase off the coyote population.

d
no; since the skunks also eat the mice, there may or may not be enough mice for the coyotes to maintain their population.
Chemistry
1 answer:
Irina18 [472]2 years ago
6 0

Answer:

b

Explanation:

even if the skunks are gone it doesn't affect the population of the coyote

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What is the molarity of a solution containing 18.2 g of KCl in 215 mL of KCl solution?
bulgar [2K]

Answer:

The sum would be 69109.4944 ml if that's what you were asking

3 0
3 years ago
. In lab we used 40 ml of 6M NaOH in making soap.<br>How many moles of NaOH was in this volume?​
Firdavs [7]

Hey there!:

Molarity of NaOH = 6 M or 6 mol/L

Volume of NaOH = 40 mL

Therefore , number of moles of NaOH:

40 mL  =( 6 mol / 1000 mL)*40=

6/ 1000 * 40 =>  0.24 moles of NaOH

Hope this helps!

8 0
3 years ago
Write the balanced Ka and Kb reactions for HSO3- in water. Be sure to include the physical states of each species involved in th
Hunter-Best [27]

Answer:

Ka = [H₃O⁺] [SO₃²⁻] / [HSO₃⁻]

Kb = [OH⁻] [H₂SO₃] / [HSO₃⁻]

Explanation:

An amphoteric substance as HSO₃⁻ is a substance that act as either an acid or a base. When acid:

HSO₃⁻(aq) + H₂O(l) ⇄ H₃O⁺(aq) + SO₃²⁻(aq)

And Ka, the acid dissociation constant is:

<h3>Ka = [H₃O⁺] [SO₃²⁻] / [HSO₃⁻]</h3><h3 />

When base:

HSO₃⁻(aq) + H₂O(l) ⇄ OH⁻(aq) + H₂SO₃(aq)

And kb, base dissociation constant is:

<h3>Kb = [OH⁻] [H₂SO₃] / [HSO₃⁻]</h3>

6 0
3 years ago
When determining melting point, you need to be aware of several factors that can affect the accuracy of the measurement. Answer
sveticcg [70]

Answer:

(1) The sample should not be large, because a large sample would produce a higher and broader mp range.

(2) The rate of heating does not matter.

Explanation:

(1) The sample should not be large, because a large sample would produce a higher and broader mp range, because varying temperature range across the body will lead to inaccurate determination of melting point.

(2) In principle, the melting temperature is INDEPENDENT (not dependent) on the heating rate. so in other words, altering the heating rate does not affect the measure of melting point.

8 0
3 years ago
A waterbed mattress has the following dimensions: 210 cm X 160 cm X 25 cm. The density of water is 62.4lb/ft3. What is the weigh
artcher [175]

<u>Answer:</u> The weight of water bed in pounds is 1850.16 lb

<u>Explanation:</u>

To calculate the volume of cuboid, we use the equation:

V=lbh

where,

V = volume of cuboid

l = length of cuboid = 210 cm

b = breadth of cuboid = 160 cm

h = height of cuboid = 25 cm

Putting values in above equation, we get:

V=210\times 160\times 25=8.4\times 10^5cm^3=29.65ft^3      (Conversion factor:  1cm^3=3.53\times 10^{-5}ft^3 )

To calculate the mass of waterbed, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of waterbed = 62.4lb/ft^3

Volume of waterbed = 29.65ft^3

Putting values in above equation, we get:

62.4lb/ft^3=\frac{\text{Mass of waterbed}}{29.65ft^3}\\\\\text{Mass of waterbed}=(62.4lb/ft^3\times 29.65ft^3)=1850.16lb

Hence, the weight of water bed in pounds is 1850.16 lb

7 0
4 years ago
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