Question

Be sure to answer all parts. For an aqueous solution of sodium chloride (NaCl), determine the molarity of 4.05 L of a solution that contains 195 g of sodium chloride. M Determine the volume of this solution that would contain 4.63 moles of sodium chloride. L Determine the number of moles of sodium chloride in 25.35 L of this solution. mol

Answer 1

Answer:

$0.824\ \text{M}$

$5.62\ \text{L}$

$20.89\ \text{mol}$

Explanation:

Molar mass of NaCl = 58.44 g/mol

Mass of NaCl = 195 g

Volume of solution = 4.05 L

Molarity of solution is

$\dfrac{195}{4.05}\times \dfrac{1}{58.44}=0.824\ \text{M}$

The molarity of the solution is $0.824\ \text{M}$

Moles of NaCl = 4.63 mol

Volume is given by

$\dfrac{4.63}{0.824}=5.62\ \text{L}$

The volume of the solution that contains the required amount NaCl is $5.62\ \text{L}$

Volume of solution = $25.35\ \text{L}$

Moles of solution is given by

$0.824\times 25.35=20.89\ \text{mol}$

The number of moles of NaCl is $20.89\ \text{mol}$.