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Damm [24]
4 years ago
7

You burn a 1.5 g jellybean to warm 150 g of water. The temperature of the water increases by 15 °C. Water has a specific heat of

4.184 J/g • °C. How many joules does the jellybean have? A) 94.14 J B)941.4 J C)9414 J D)14124 J
Chemistry
1 answer:
Schach [20]4 years ago
3 0

Answer:

9414.0 J.

Explanation:

  • The amount of heat absorbed by water through burning a 1.5 g jellybean can be calculated from the relation:

<em>Q = m.c.ΔT.</em>

where, Q is the amount of heat absorbed by water,

m is the mass of water (m = 150.0 g),

c is the specific heat of water (c = 4.184 J/g °C),

ΔT is the temperature difference (final T - initial T) (ΔT = 15.0 °C).

<em>∴ Q = m.c.ΔT</em> = (150.0 g)(4.184 J/g °C)(15.0 °C) = <em>9414.0 J. </em>

  • <em>So, the jellybean have 9414.0 J that is releases to water.</em>
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3 years ago
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For the given question we use the below equation is:

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What is the volume occupied by 30.00 grams of pure gold?​
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4 years ago
What is the [OH-] in a solution if the [H*] = 1.2 x 10-3 M?
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