Combine like terms:
n^3 + 20n^ + 10n^2
= n^3 + 30n^
Divide:
=n^3 + 30n^2/10n^2
Factor:
=n^2n + 30n^2
=n^(n + 30)
= 2^2(n + 30)/10n^2
Cancel the common factor n^2:
=n + 10/10
Answer:
The measure of the third arc is 
Step-by-step explanation:
step 1
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
in this problem
Let
x----> the greater arc of the circle intercepted by the secant and the tangent
y----> the smaller arc of the circle intercepted by the secant and the tangent

----> equation A

-----> equation B
Substitute equation B in equation A and solve for y

Find the value of x

step 2
Find the measure of the third arc
Let
z------> the measure of the third arc
we know that
-----> complete circle
substitute the values and solve for z


Okay I am going to explain to you and show you how to get the correct answer.
Fist you need to find the Greatest common factor which is 45 because 5×9=45
8/9=40/45
+3/5=27/45
__________
67/45 is reduced to 1 22/45
5 goes into 45 9 times so 3 times 7 equals 27 and 9 goes into 45 5 times so 8 times 5 equals 40 you add both numbers up and get 67. 67 can't go into 45 so you subtract 67 from 45. 45 goes into 67 1 time so that is your whole the number. 22 is left over so that is your numerator. The denominator remains the same.
Answer:

Step-by-step explanation:
To find the circumference of a circle, you can multiply the value of the diameter of the circle with the value of pi.


84j is the equivalent.
Just add 36 to 48 and put the j on.