Answer:
perimeter is 4 sqrt(29) + 4pi cm
area is 40 + 8pi cm^2
Step-by-step explanation:
We have a semicircle and a triangle
First the semicircle with diameter 8
A = 1/2 pi r^2 for a semicircle
r = d/2 = 8/2 =4
A = 1/2 pi ( 4)^2
=1/2 pi *16
= 8pi
Now the triangle with base 8 and height 10
A = 1/2 bh
=1/2 8*10
= 40
Add the areas together
A = 40 + 8pi cm^2
Now the perimeter
We have 1/2 of the circumference
1/2 C =1/2 pi *d
= 1/2 pi 8
= 4pi
Now we need to find the length of the hypotenuse of the right triangles
using the pythagorean theorem
a^2+b^2 = c^2
The base is 4 ( 1/2 of the diameter) and the height is 10
4^2 + 10 ^2 = c^2
16 + 100 = c^2
116 = c^2
sqrt(116) = c
2 sqrt(29) = c
Each hypotenuse is the same so we have
hypotenuse + hypotenuse + 1/2 circumference
2 sqrt(29) + 2 sqrt(29) + 4 pi
4 sqrt(29) + 4pi cm
Answer: bd=8 dc=2 and ae=4 so value of ab=16
Step-by-step explanation:
1/3 of a foot = 4 inches
(4^3)*3=
(4*4*4)*3=
(16*4)*3=
64*3=
192
In order to make point D as the vertex in the construction as triangle ABC, the third arc should cross the second arc.
<h3>What is an arc?</h3>
In Geometry, an arc can be defined as a trajectory that is generally formed when the distance from a given point has a fixed numerical value.
In order to make point D as the vertex in the construction as triangle ABC, you must ensure that the third arc crosses the second arc as illustrated in image attached below.
Read more on arc here: brainly.com/question/20594692
#SPJ1
A. 6 times 1=6 is the answer to which of the following is an example of identical property of multiplication