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2 years ago

Can y’all plz help me

Mathematics

1 answer:

Zinaida [17]2 years ago

4 0

Answer:

if you are using a GPS it would be absolute location

Step-by-step explanation:

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Which equation describes the graph? (In the photo)

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Answer:

C. The slope is 3 and the y-intercept is -3

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2 years ago

I need help finding the area

BabaBlast [244]

Answer:

Step-by-step explanation:

A=a+b/2*hA=12

A=12*12/2

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2 years ago

What's 7⁄8 as a decimal? A. 8.7 B. .875 C. .78 D. 7.8

LuckyWell [14K]

7/8 is equal to 0.875

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3 years ago

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Which is the best approximation for the value of 160−−−√?

melamori03 [73]

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3 years ago

Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.

Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

$|AB|=\sqrt{(4--1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{5^2+(0)^2}$

$\Rightarrow |AB|=\sqrt{25}$

$\Rightarrow |AB|=5 units$ .

The length of side BC

$|BC|=\sqrt{(3-4)^2+(-1-2)^2}$

$\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}$

$\Rightarrow |BC|=\sqrt{1+9}$

$\Rightarrow |BC|=\sqrt{10}$

The length of side AC

$|AC|=\sqrt{(3--1)^2+(-1-2)^2}$

We simplify to obtain;

$|AC|=\sqrt{(3+1)^2+(-3)^2}$

$\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}$

$|AC|=\sqrt{16+9}$

$|AC|=\sqrt{25}$

$|AC|=5\:units$

Since $|AC|=5\:units=|AB|$ , the given triangle is an isosceles triangle.

The correct answer is

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3 years ago

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