3 years ago

Can y’all plz help me

1 answer:

4 0

Answer:

if you are using a GPS it would be absolute location

Step-by-step explanation:

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Artist 52 [7]

AE x BE = DE x CE

6x5 = 30

6 x DE = 30

DE = 30/6 =5

DC = DE +CE = 5+6 =11

Answer is C) 11

8 0

3 years ago

Julli [10]

Sometimes I’m pretty sure

6 0

3 years ago

marin [14]

Answer:$39

Step-by-step explanation:

7 0

3 years ago

elena55 [62]

Answer:

Factoring the term $(5x^5) - (80x^3)$ we get $\mathbf{5x^3(x-4)(x+4)}$

Step-by-step explanation:

We need to factor the term $(5x^5) - (80x^3)$

First we can see that $5x^3$ is common in both terms

So, taking $5x^3$ common:

$(5x^5) - (80x^3)\\=5x^3(x^2-16)$

We can write $x^2-16$ as $(x)^2-(4)^2$

$=5x^3((x)^2-(4)^2)$

Now we can solve $(x)^2-(4)^2$ using the formula: $a^2-b^2=(a+b)(a-b)$

We can write:

$=5x^3((x)^2-(4)^2)\\=5x^3(x-4)(x+4)$

So, factoring the term $(5x^5) - (80x^3)$ we get $\mathbf{5x^3(x-4)(x+4)}$

4 0

3 years ago

neonofarm [45]

As we may be dividing fractions...
$\frac{21}{2} \div \frac{3}{16} = \frac{21}{2} \times \frac{16}{3} = \frac{7}{1} \times \frac{8}{1} = 56$

5 0

3 years ago