Answer:
answer is -1 according to calculation
Question:
Charlotte has been working for her company for x years. Travis has been working for the same company exactly 3 years longer than Charlotte. What is the range of the relationship?
A- y>0
B- y>3
C. y<3
D. 0
Answer:
y > 3
Step-by-step explanation:
Number of years Charlotte has worked = x
Number of years Travis has worked = y. ie, y = 3+x
Let's assume the function reaches its lowest point at 3. There could also be a higher value for this function.
We now have:
f(x) = y > 3
Since Travis has been working for the same company exactly 3 years longer than Charlotte the range of the relationship is y>3
C multiply 1/2 by 10 and 1/5 by 2
The sequence above is geometric progression.
The nth term of such sequence is given by;
Tn = ar∧(n-1),
Where a⇒first term and
r⇒common ratio
So, 1st term = 5×1.25∧(1-1) = 5×1.25∧0 =5
2nd term = 5×1.25∧(2-1) = 5×1.25 = 6.25
3rd term = 5×1.25∧(3-1) = 5×1.25² = 7.8125
4th term = 5×1.25∧(4-1) =5×1.25³ = 9.765625
5th term = 5×1.25∧(5-1) = 5×1.25∧4 = 12.20703125
6th term = 5×1.25∧(6-1) = 5×1.25∧5 = 15.25878909
