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2 years ago

HELP with this please!!

Mathematics

2 answers:

puteri [66]2 years ago

6 0

$~~~~\dfrac{12}{x^2 -49} \cdot \dfrac{x^2+9x+14}{9}\\\\\\=\dfrac{4}{x^2 -7^2}\cdot \dfrac{x^2 + 7x +2x +14}{3}\\\\\\=\dfrac{4}{(x+7)(x-7)} \cdot \dfrac{x(x+7)+2(x+7)}{3}\\\\\\=\dfrac{4}{(x+7)(x-7)}\cdot \dfrac{(x+7)(x+2)}{3}\\\\\\=\dfrac{4(x+2)}{3(x-7)}$

densk [106]2 years ago

3 0

Answer:

$\frac{4(x + 2)}{3(x - 7)}$

Step-by-step explanation:

Hello!

We can simplify this by factoring, and cross reducing.

<h3>Simplify</h3>

$\frac{12}{x^2 - 49} * \frac{x^2 + 9x + 14}{9}$
$\frac{12}{(x+7)(x - 7)} * \frac{(x + 2)(x + 7)}{9}$
$\frac{12(x + 2)}{9(x - 7)}$
$\frac{4(x + 2)}{3(x - 7)}$

The final simplified form is $\frac{4(x + 2)}{3(x - 7)}$

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Hope this helps, mate!

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Hope this helps, mate! :)

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