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stellarik [79]
2 years ago
9

HELP with this please!!

Mathematics
2 answers:
puteri [66]2 years ago
6 0

~~~~\dfrac{12}{x^2 -49} \cdot \dfrac{x^2+9x+14}{9}\\\\\\=\dfrac{4}{x^2 -7^2}\cdot \dfrac{x^2 + 7x +2x +14}{3}\\\\\\=\dfrac{4}{(x+7)(x-7)} \cdot  \dfrac{x(x+7)+2(x+7)}{3}\\\\\\=\dfrac{4}{(x+7)(x-7)}\cdot  \dfrac{(x+7)(x+2)}{3}\\\\\\=\dfrac{4(x+2)}{3(x-7)}

densk [106]2 years ago
3 0

Answer:

\frac{4(x + 2)}{3(x - 7)}

Step-by-step explanation:

Hello!

We can simplify this by factoring, and cross reducing.

<h3>Simplify</h3>
  • \frac{12}{x^2 - 49} * \frac{x^2 + 9x + 14}{9}
  • \frac{12}{(x+7)(x - 7)} * \frac{(x + 2)(x + 7)}{9}
  • \frac{12(x + 2)}{9(x - 7)}
  • \frac{4(x + 2)}{3(x - 7)}

The final simplified form is \frac{4(x + 2)}{3(x - 7)}

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