So to work this out we need to find the 4th root of each of those and pick the one that gives an integer.
A:
![\sqrt[4]{1.6*10^1^1} = 632.455...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E1%7D%20%3D%20632.455...)
This is a decimal therefore <em>not</em> an integer.
B:
![\sqrt[4]{1.6*10^1^2} =1124.682...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E2%7D%20%3D1124.682...)
Again a decimal, therefore <em>not </em>an integer.
C:
![\sqrt[4]{1.6*10^1^3} =2000](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E3%7D%20%3D2000)
This is a whole number, so it <em>is </em>an integer.
D:
![\sqrt[4]{1.6*10^1^4} =3556.558...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E4%7D%20%3D3556.558...)
Decimal, therefore <em>not </em>an integer
E:
![\sqrt[4]{1.6*10^1^5} =6324.555...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E5%7D%20%3D6324.555...)
Again a decimal, <em>not</em> an integer.
The only one that gives an integer when put to the 4th root is C, therefore:
could be A^4, as the 4th root of it is an integer.
Answer:
x=13
Step-by-step explanation:
One person being nervous around strangers is assumed independent of other people behaviour. Then, the multiplication rule can be applied as
both nervous = 0.14*0.14 = 0.0196 = 1.96%
one is nervous, one is not nervous = 0.14*(1-0.14) = 0.1204 = 12.04%
At least one nervous = 1.96% + 12.04% = 14%
I hope this helps you
boys+4=girls
boys+girls=26
boys+boys+4=26
2.boys=22
boys=11
girls=15
Answer:
61°
Step-by-step explanation:
, QO Bisector
, Algebra
, Algebra/Sub