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soldi70 [24.7K]
3 years ago
9

PLEASE HELP ME PRETTY PLEASE

Mathematics
1 answer:
aksik [14]3 years ago
4 0

Answer:

The approximate height of the tree is 4.6 m

Step-by-step explanation:

Distance between the base of tree and arborist = 8 m

So, Base = 8 m

The angle of elevation to one tree is 30°

We are supposed to find What is the approximate height of the tree?

Using trigonometric property:

tan \theta = \frac{Perpendicular}{Base}\\Tan 30^{\circ}=\frac{Height}{8}\\\frac{1}{\sqrt{3}}=\frac{Height}{8}\\\frac{8}{\sqrt{3}}=Height\\4.618=Height

So,  the approximate height of the tree is 4.6 m

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AleksAgata [21]

Answer:

Part 1) sin(B)=\frac{21}{29}

Part 2) csc(A)=\frac{29}{20}

Part 3) cot(A)=\frac{21}{20}

Step-by-step explanation:

<u><em>The complete question is</em></u>

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

sin(B)=\frac{AC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(B)=\frac{21}{29}

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

csc(A)=\frac{1}{sin(A)}

sin(A)=\frac{BC}{AB} -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(A)=\frac{20}{29}

therefore

csc(A)=\frac{29}{20}

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

cot(A)=\frac{1}{tan(A)}

tan(A)=\frac{BC}{AC} -----> by TOA (opposite side divided by the adjacent side)

substitute the values

tan(A)=\frac{20}{21}

therefore

cot(A)=\frac{21}{20}

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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What is the definition of present value?
Bezzdna [24]

Answer:

the value in the present of a sum of money, in contrast to some future value it will have when it has been invested at compound interest.

Step-by-step explanation:

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A manufacturing firm tests job applicants. Test scores are normally distributed with a mean of 500 and a standard deviation of 5
Blababa [14]

Answer:

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = 0.0228

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given mean of the Population = 500

Given standard deviation of the Population = 50

Let 'X' be the random variable in normal distribution

Given  X = 600

Z = \frac{x-mean}{S.D} = \frac{600-500}{50} = \frac{100}{50} =2

<u><em>Step(ii)</em></u>:-

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = P(z≥2)

                  = 0.5 - A(2)

                 = 0.5 -0.4772

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<u><em>Final answer</em></u>:-

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = 0.0228

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