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3 years ago

PLEASE HELP ME PRETTY PLEASE

Mathematics

1 answer:

aksik [14]3 years ago

4 0

Answer:

The approximate height of the tree is 4.6 m

Step-by-step explanation:

Distance between the base of tree and arborist = 8 m

So, Base = 8 m

The angle of elevation to one tree is 30°

We are supposed to find What is the approximate height of the tree?

Using trigonometric property:

$tan \theta = \frac{Perpendicular}{Base}\\Tan 30^{\circ}=\frac{Height}{8}\\\frac{1}{\sqrt{3}}=\frac{Height}{8}\\\frac{8}{\sqrt{3}}=Height\\4.618=Height$

So, the approximate height of the tree is 4.6 m

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A density curve for all the possible temperatures between 0°F and 40°F is a

My name is Ann [436]

Answer:

B. 0.025

Step-by-step explanation:

6 0

3 years ago

Find the HCF of 27, 63, 54 using prime factorization method.

Step2247 [10]

Answer:

27 = 3 , 3, 3

63= 3 , 3, 7

54= 3 , 3, 3, 2

HCF OF 27, 63 AND 54 = 3 X 3 = 9

HOPE THIS HELPS YOU MATE Plz mark it as brainliest answer 

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7 0

3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

Please I need x and y

Kryger [21]

It could be anything they are both variables.

3 0

4 years ago

What are the solutions of the compound inequality 2d + 3 ≤ –11 or 3d – 9 > 15?

jolli1 [7]

Answer:

A. d ≤ –7 or d > 8.

Step-by-step explanation:

Given : 2d + 3 ≤ –11 or 3d – 9 > 15.

To find : What are the solutions of the compound inequality .

Solution : We have given 2d + 3 ≤ –11 or 3d – 9 > 15.

For 2d + 3 ≤ –11

On subtracting both sides by 3

2d ≤ –11 - 3 .

2d ≤ –14.

On dividing both sides by 2 .

d ≤ –7.

For 3d – 9 > 15.

On adding both sides by 9.

3d > 15 + 9 .

3d > 24 .

On dividing both sides by 3 .

d > 8 .

So, A. d ≤ –7 or d > 8.

Therefore, A. d ≤ –7 or d > 8.

7 0

3 years ago