Samantha bought 10 identical shirts for $25. If she bought 25 of those same shirts, how much will she pay?

Mathematics

2 answers:

inn [45]2 years ago

7 0

Answer: 625.

eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee.

This might be wrong because I'm not very good at math...

tatiyna2 years ago

5 0

Answer:

72.50

Step-by-step explanation:

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Kylie buys a ceramic case priced at $75. Shipping and handling are an additional 9 2/5% of the price. How much shopping and hand

salantis [7]

$\bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
75&100\\
x&9\frac{2}{5}
\end{array}\implies \cfrac{75}{x}=\cfrac{100}{9\frac{2}{5}}\implies \cfrac{75}{x}=\cfrac{100}{\frac{9\cdot 5+2}{5}}$

$\bf \cfrac{75}{x}=\cfrac{\frac{100}{1}}{\frac{47}{5}}\implies \cfrac{75}{x}=\cfrac{100}{1}\cdot \cfrac{5}{47}\implies \cfrac{75}{x}=\cfrac{500}{47}\implies 75\cdot 47=500\cdot x
\\\\\\
\cfrac{3525}{500}=x\implies \cfrac{141}{20}=x\implies 7.05=x$

7 0

3 years ago

An arc of a circle is 3πm long, and it subtends an angle of 72° at the center of the circle. Find the radius of the circle.

Alex777 [14]

72⁰_______3π m
360⁰______15π m

C = 15π = 2π r
r = 7•5 m

8 0

3 years ago

Use the definition of a Taylor series to find the first three non zero terms of the Taylor series for the given function centere

Ket [755]

Answer:

$e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...$

$\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n$

Step-by-step explanation:

<u>Taylor series</u> expansions of f(x) at the point x = a

$\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...$

This expansion is valid only if $\text{f}\:^{(n)}(a)$ exists and is finite for all $n \in \mathbb{N}$ , and for values of x for which the infinite series converges.

$\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1$

$\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...$

$\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}$