Answer:
Rock D.
Step-by-step explanation:
We can assume that the force that the catapult does is always the same.
So, here we need to remember Newton's second law:
F = m*a
force equals mass times acceleration.
Where acceleration is the rate of change of the velocity.
So, if we want the rock to hit closer to the catapult, the rock must be less accelerated than rock B.
So, we can rewrite:
a = F/m
So, as larger is the mass of the rock, smaller will be the acceleration of the rock after it leaves the catapult (because the mass is in the denominator). So if we want to have a smaller acceleration, we need to choose a rock with a larger mass than rock B.
Assuming that the mass depends on the size, the only one that has a mass larger than rock B is rock D.
So we can assume that rock D is the correct option.
Using the diagram, we can conclude that the radius is 10 feet, and the height is 6 feet.
Plug in the values for radius and height into the equation.
V = π10^2*6
Simplify in terms of pi.
V = 600π
Round pi to 3.14 and multiply by 600.
V = 1,884
1,884 cubic feet is your answer.
In the image you provided, I do not see a fourth option that includes 1,884 cubic feet. I would assume that the camera did not take a full picture of the answer choices.
I am not very good you should probably ask someone else sorry
