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antoniya [11.8K]
4 years ago
14

Aflati x numar natural nul

Mathematics
1 answer:
Advocard [28]4 years ago
5 0
Exceseuor if im wrong sorry
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Look at the picture <br> .<br> .<br> .<br> .<br> ..<br> .<br> .<br> .<br> .<br> .<br> .
frozen [14]

Answer:

1 D

2 A

and

3rd will be B and C

if you want explanation you can comment

4 0
3 years ago
WILL MARK B!<br> Please I need help I have a quiz
MArishka [77]

Answer:

a) 2x² - x + 3 = x(2x + 1) - 2x

<=> 2x² - x + 3 = 2x² + x - 2x

<=> 3 - x = - x

<=> 3 = 0

=> no solution

b) x/2 - x/3 - x/4 = 1/12

\frac{6x}{12}  -  \frac{4x}{12}  -  \frac{3x}{12}  =  \frac{1}{12}  \\  \\  \frac{ - x}{12}  =  \frac{1}{12}  \\  \\  =  >  - x = 1 \\  \\  \\  <  =  > x = 1

=> the euqation has the solution x = 1

c) |x - 5| = 2|x|

=> x - 5 = 2x

or x - 5 = -2x

<=> x = -5

or 3x = 5

<=> x = -5

x = -5or x = 5/3

d) defined conditions: 2 - x 》 0

<=> x 《 2

we have:

\sqrt{x + 4}  = 2 - x \\  <  =  > x + 4 = (2 - x) {}^{2}   \\  <  =  > x + 4 =  {x}^{2}  - 4x + 4 \\  <  =  >  {x}^{2}  - 5x = 0 \\  <  =  > x(x - 5) = 0 \\

<=> x = 0 (because x 《 2)

e)

\sqrt{5}  =  \frac{1}{25 {}^{x} }  \\   =  > 5 =  \frac{1}{25 {}^{2x} }  \\  <  =  > 5.25 {}^{2x}  = 1  \\ <  =  >  5.5 {}^{4x}  = 1 \\  <  =  > 5 {}^{4x + 1}  = 1 \\  =  > 4x + 1 = 0

<=> x = -1/4

3 0
3 years ago
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Any help greatly appreciated! Thank you in advance.
Nutka1998 [239]

Answer:

C $210.00 Becuase each time she bought she lost 100 dollars:)

Step-by-step explanation:


7 0
4 years ago
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How do you solve Andrea is selling candles as a
masya89 [10]

Answer:500

Step-by-step explanation: did she sell the candies for 10$ or no

3 0
4 years ago
I need help with 1 and 2
oee [108]
1) -149, -1; -148, -2; -147, -3
2) No, according to the commutative property of addition, it does not matter the order they are put in.

Hope this helps!
6 0
4 years ago
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