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frozen [14]
2 years ago
15

Given f(x)=2/x^2+3x-10.

Mathematics
1 answer:
zmey [24]2 years ago
4 0

The function  f(x)=2/x²+3x-10 is negative for all x < -5 option second "is negative for all x < -5" is correct.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

\rm f\left(x\right)=\dfrac{2}{x^2}+3x-10

f(x) is positive for all x < -5

Plug x = -4

f(-4) = -21.875

The above statement is not true

f(x) is negative for all x < -5

Plug x = -4

f(-4) = -21.875

The above statement is true

f(x) is positive for all x < 2

Plug x = 1

f(1) = -5

The above statement is not true

f(x) is negative for all x > 2

Plug x = 3

f(3) = -0.777

The above statement is not true

Thus, the function  f(x)=2/x²+3x-10 is negative for all x < -5 option second "is negative for all x < -5" is correct.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

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Answer:

Not sure by the way the question is asked but I think the answer is x=(y-1)/4

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find the least length of a rod which can be cut into exactly epual strips,each of either 36cm or 42cm in length​
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Step-by-step explanation:

so, we need to find the smallest common multiple of 36 and 42.

that is the smallest number I can divide both by 36 and 42 without remain.

let's use the method of basic prime factors (we start with the smallest fitting prime number - 2 is a prime number too - and divide as often as possible, then continue with the next bigger prime number, until there is nothing left to divide) :

36 / 2 = 18

18 / 2 = 9

9 / 3 = 3

3 / 3 = 1 finished

therefore,

36 = 2×2×3×3

42 / 2 = 21

21 / 3 = 7

7 / 5 does not work

7 / 7 = 1 finished

therefore,

42 = 2×3×7

to find the smallest common multiple (SCM) we check the maximum length of each prime factor sequence.

and we see 2 times 2, 2 times 3 and 1 time 7.

so, the SCM = 2×2×3×3×7 = 252.

there is no smaller number that can be divided by both 36 and 42 without remain.

so, the rod must be at least 252 cm long to cut it into equally long pieces of either 36 cm (7 pieces) or 42 cm (6 pieces).

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