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N76 [4]
2 years ago
8

Last month, a basketball team scored 83, 84, 85, 87, 89, 88, 67, 79, and 81 points in their games. Which data value(s) are outli

ers? Select all that apply.
Mathematics
1 answer:
Leto [7]2 years ago
6 0

The data value that is an outlier is 67

<h3>How to determine the outlier?</h3>

The dataset is given as:

83, 84, 85, 87, 89, 88, 67, 79, and 81

To determine the outlier, we select the data values that are relatively far from others

In the above dataset, the data element 67 is far from other data values

Hence, the data value that is an outlier is 67

Read more about outlier at:

brainly.com/question/3631910

#SPJ1

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What is the answer to: (51 + 11.22 + 35.92)?
In-s [12.5K]

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It would equal 98.14

Step-by-step explanation:


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If g(x) = 4x^2 - 16 were shifted 7 units to the right and 3 down, what would the
Kitty [74]

Answer:

The new equation is h(x)=4(x-7)^2-19

Step-by-step explanation:

Given : Function g(x) = 4x^2 - 16 were shifted 7 units to the right and 3 down.

To find : What would the  new equation be?​

Solution :

Shifting to the right with 'a' unit is

f(x)→f(x-a)

So, shifting g(x) 7 units to the right is

h(x) = 4(x-7)^2-16

Shifting to the down with 'b' unit is

f(x)→f(x)-b

So, shifting g(x) 3 units down is

h(x)=(4(x-7)^2-16)-3

h(x)=4(x-7)^2-19

The new equation is h(x)=4(x-7)^2-19

8 0
3 years ago
Dyami lives x miles from the school. Karla lives 2/3 further than that from the school.
Hatshy [7]

Answer:

Where is the schools coordinates subtract two thirds from whatever the schools coordinates are and you will have your answer for Dyami

Step-by-step explanation:

3 0
3 years ago
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When purchasing bulk orders of​ batteries, a toy manufacturer uses this acceptance sampling​ plan: Randomly select and test 56 b
nydimaria [60]

Answer:

98.1% chance of being accepted

Step-by-step explanation:

Given:

sample size,n=56

acceptance condition= at most 2 batteries do not meet specifications

shipment size=7000

battery percentage in shipment that do not meet specification= 1%

Applying binomial distribution

<h3>P(x)=∑ᵇₐ=₀ (n!/a!(n-a)!)p^a (1-p)^(n-a)</h3>

In this formula, a is the acceptable number of defectives;

 n is the sample size; 

p is the fraction of defectives in the population.  

Now putting the value

a= 2

n=56

p=0.01

\frac{56!}{0!\left(56-0\right)!}\left(0.01\right)^0\:\left(1-0.01\right)^{\left(56-0\right)} + \frac{56!}{1!\left(56-1\right)!}\left(0.01\right)^1\:\left(1-0.01\right)^{\left(56-1\right)} +\:\frac{56!}{2!\left(56-2\right)!}\left(0.01\right)^2\:\left(1-0.01\right)^{\left(56-2\right)}

=0.56960+0.32219+0.08949

After summation, we get 0.981 i.e. a 98.1% chance of being accepted.  As this is such a high chance, we can expect many of the shipments like this to be accepted!

7 0
3 years ago
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