Answer:
The answer is B.
Step-by-step explanation:
You have to substitute x = 2, into the equation of y :
Nice
4s=amount of grams of protine in straberry for s ounces
3b=amount of grams of protine in banana for b ouces
total ounces is 6
s+b=6
total grams is 22
4s+3b=22
s+b=6
4s+3b=22
those are the 2 equations
a.
s+b=6
4s+3b=22
b. elmination, we can elminate alll the b's and have 1s left
c.
multiply first equaiton by -3 and add to second
4s+3b=22
<u>-3s-3b=-18 +</u>
1s+0b=4
s=4
sub
s+b=6
4+b=6
minus 4
b=2
4 oz straberry
2 oz banana
Answer:
the answer to it is A. 75
I don’t know I need points
5)
a. The equation that describes the forces which act in the x-direction:
<span> Fx = 200 * cos 30 </span>
<span>
b. The equation which describes the forces which act in the y-direction: </span>
<span> Fy = 200 * sin 30 </span>
<span>c. The x and y components of the force of tension: </span>
<span> Tx = Fx = 200 * cos 30 </span>
<span> Ty = Fy = 200 * sin 30 </span>
d.<span>Since desk does not budge, </span><span>frictional force = Fx
= 200 * cos 30 </span>
<span> Normal force </span><span>= 50 * g - Fy
= 50 g - 200 * sin 30
</span>____________________________________________________________
6)<span> Let F_net = 0</span>
a. The equation that describes the forces which act in the x-direction:
(200N)cos(30) - F_s = 0
b. The equation that describes the forces which act in the y-direction:
F_N - (200N)sin(30) - mg = 0
c. The values of friction and normal forces will be:
Friction force= (200N)cos(30),
The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N
Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N
