What is the x-coordinate of the vertex of the parabola whose equation is y = 3x² + 9x?

Mathematics

1 answer:

saveliy_v [14]2 years ago

3 0

Answer: -3/2

Step-by-step explanation:

The axis of symmetry, and thus the x-coordinate of the vertex, is given by $x=-\frac{b}{2a}$

So, the answer is $x=-\frac{9}{2(3)}=\boxed{-\frac{3}{2}}$

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If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the leading coefficient of denominator.

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The value of P - Q as described in the question above is; P -Q = 2.

According to the question;

P = number of primes less than 100
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Since, we are required to determine what the value of P-Q is;

The value of P-Q is simply the number of primes between 90 and 100.

The prime numbers between 90 and 100 are; 91 and 97.

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