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Alekssandra [29.7K]
2 years ago
6

What is the x-coordinate of the vertex of the parabola whose equation is y = 3x² + 9x?

Mathematics
1 answer:
saveliy_v [14]2 years ago
3 0

Answer: -3/2

Step-by-step explanation:

The axis of symmetry, and thus the x-coordinate of the vertex, is given by x=-\frac{b}{2a}

So, the answer is x=-\frac{9}{2(3)}=\boxed{-\frac{3}{2}}

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The sum of three numbers is 121 The third number is 3 times the second. The first number is 6 times the second. The first number
Mama L [17]

Answer:

The first number is

72.6

Step-by-step explanation:

Let second number be x.

First number= 6x

Third number= 3x

According to question,

6x+x+3x=121

or, 10x=121

or,x=121/10=12.1

First number= 6x=6×12.1=72.6

Third number=3x=3×12.1=36.3

3 0
3 years ago
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The perimeter Of a rectangle is 30 inches if it’s Lance is three times it’s width find the dimensions.
Marat540 [252]

Answer:

Width: 3.75

Length: 11.25

7 0
3 years ago
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Can anyone help me out
bezimeni [28]
The answer is 1:3 because 1/4 has nuts and 3/4 don’t
5 0
3 years ago
I need help with this(explain). what is the value of the expression 2x^2 + 3xy - 4y^2 when x=2 and y= -4 ​
Strike441 [17]

Answer: The answer is -80

Step-by-step explanation:

2(2^2)+(3)(2)(−4)−4(−4)^2

2(2^2)+(3)(2)(−4)−4(−4)^2

=−80

4 0
3 years ago
A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes
hammer [34]

Answer:

a) The probability that this whole shipment will be​ accepted is 30%.

b) Many of the shipments with this rate of defective aspirin tablets will be rejected.

Step-by-step explanation:

We have a shipment of 3000 aspirin tablets, with a 5% rate of defects.

We select a sample of size 48 and test for defectives.

If more than one aspirin is defective, the batch is rejected.

The amount of defective aspirin tablets X can be modeled as a binomial distribution random variable, with p=0.55 and n=48

We have to calculate the probabilities that X is equal or less than 1: P(X≤1).

P(X\leq1)=P(X=0)+P(X=1)\\\\\\P(0)=\binom{48}{0}(0.05)^0(0.95)^{48}=1*1*0.0853=0.0853\\\\\\P(1)=\binom{48}{1}(0.05)^1(0.95)^{47}=48*0.05*0.0897=0.2154\\\\\\P(X\eq1)=0.0853+0.2154=0.3007

8 0
3 years ago
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