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Novay_Z [31]
3 years ago
11

I really need this answered!

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
7 0

Answer:

Its AA similaroty theorem

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What is the area of this figure? Enter your answer in the box.
Basile [38]
Luckily for us, the diagram already divided this figure into separate polygons. What I will be explaining is basically the addition of the areas of all the separate polygons. The area of the uppermost triangle is:

1/2 x b x h
= 1/2 x 20 x 8
(the base is 20, because in a parallelogram, opposite sides are congruent)
=10 x 8
= 80 in. squared

The next polygon we will be taking the area of is the parallelogram with the base length of 20 and the height of 16.

Area = b x h
= 20 x 16
= 320 in. squared

Now all we have left to do is add the two areas to obtain the total area.

Total Area = 320 + 80 = 400 in. squared


3 0
3 years ago
Select the correct answer from each drop-down menu.
Aleksandr [31]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
You have a loan for $200,000 at 8.5% annual simple interest. What is your monthly interest payment?
Sergeu [11.5K]

Answer:

c. 1,417

Step-by-step explanation:

200,000 (8.5%) = 17,000

17,000 / 12 = 1,416.67 or 1,417

5 0
3 years ago
Answer pls pls pls pls
Andru [333]

Answer:

7

Step-by-step explanation:

3 0
3 years ago
Find the particular solution that satisfies the differential equation and the initial condition.
Vesnalui [34]

Answer:

1) y =4x^2 +7

2) y =7s^2 -3s^4 +181

Step-by-step explanation:

Assuming that our function is y = f(x) for the first case and y=f(s) for the second case.

Part 1

We can rewrite the expression like this:

\frac{dy}{dx} =8x

And we can reorder the terms like this:

dy = 8 x dx

Now if we apply integral in both sides we got:

\int dy = 8 \int x dx

And after do the integrals we got:

y = 4x^2 +c

Now we can use the initial condition y(0) =7

7 = 4(0)^2 +c, c=7

And the final solution would be:

y =4x^2 +7

Part 2

We can rewrite the expression like this:

\frac{dy}{ds} =14s -12s^3

And we can reorder the terms like this:

dy = 14s -12s^3 dx

Now if we apply integral in both sides we got:

\int dy = \int 14s -12s^3 ds

And after do the integrals we got:

y = 7s^2 -3s^4 +c

Now we can use the initial condition y(3) =1

1 = 7(3)^2 -3(3)^4 +c, c=1-63+243=181

And the final solution would be:

y =7s^2 -3s^4 +181

7 0
3 years ago
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