Start by writing the system down, I will use
to represent 

Substitute the fact that
into the first equation to get,

Simplify into a quadratic form (
),

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

which then must factor into

And the solutions will be
.
Clearly for small coefficients like ours
, this is very easy to figure out. To get 5 and 6 we simply say that
.
This fits the definition as
and
.
So as mentioned, solutions will equal to
but these are just x-values in the solution pairs of a form
.
To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.
So the solution pairs are
and
.
Hope this helps :)
Answer:
B
Step-by-step explanation:
$5.20 is about $5.00, 21 is about 20, so $5.00 * 20 *4 = $400.
Checking this: $5.20 * 21 * 4 = $436.80
Answer:
no solution is ur right answer
Step-by-step explanation:
mark ‼️ it brainliest if it helps you ❤️
<h3>
Answer: Choice A which is (m+6)^2</h3>
Explanation:
Think of two numbers that multiply to 36 and add to 12. Those two numbers are 6 and 6
6+6 = 12
6*6 = 36
So we can factor it into (m+6)(m+6). Use the FOIL rule to expand it out to get m^2+12m+36 back again.
The expression (m+6)(m+6) is the same as (m+6)^2
Isolate the variable by dividing each side by factors that don't contain the variable.
f=e-g/d