C = 220T + 1890.
Solve the equation for T.
220T = C - 1890
T = C/220 - 8.6
The steel produced is expected to be sold at a price of $310 per ton.
310 $/ton is a rate or slope. Write a linear equation where x is tons of steel produced and y is selling price of the steel.
y = 310x
Write and solve an equation to find the amount of steel produced if the selling price is equal to the cost of production.
* Here, note that the cost of production and tons of steel in the first equation is in the millions. The equation we just wrote for the selling price was in x tons of steel. This only matters in regards to the units you specify because; million/million = 1
The unit multiplier of all variables must be specified as same. Either everything is in millions or not.
Here, I'll leave everything in millions, change x (tons of steel) to T (mill tons steel) and "y" to "S" in million dollars selling price.
S = 310T
Set equal to Cost equation.
220T + 1980 = 310T
Solve for T, million tons of steel produced.
1980 = 310T - 220T
1980 = 90T
T = 1980/90
T = 22 million tons steel produced
Answer:

Step-by-step explanation:
The equation of the line that is parallel to the line we are trying to find is

We can recall that when two lines are parallel it means that they have the same slope. Therefore the slope of the line we are trying to find is also -4. We now know that:

Therefore the equation of the line is:


The amount of water in the pool after t minutes is modeled by the linear function
, hence it is a function of time.
A <em>linear function</em> for the amount of water in the pool, considering that it is <u>drained at a rate of a gallons per minute</u>, is modeled by:

- In which V(0) is the initial volume.
In this problem, draining her hot tub at a rate of <u>5.5 gallons per minute</u>, hence
, and:

Which is a function of time.
To learn more about linear functions, you can take a look at brainly.com/question/13488309
Answer:
They are taking 12 2 credit courses
The are taking 4 1 credit courses
Step-by-step explanation:
x = 1 credit courses
y = 2 credit courses
The number of courses is 16
x+y = 16
The number of credits is 28 so multiply the course by the number of credits
1x+2y=28
Subtract the first equation from the second equation
x+2y =28
-x-y=-16
-----------------
y = 12
They are taking 12 2 credit courses
We still need to find the 1 credit courses
x+y = 16
x+12= 16
Subtract 12 from each side
x-12-12 = 16-12
x =4
The are taking 4 1 credit courses