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2 years ago

Please help, I'm stuck on this answer.

2 answers:

8 0

I agree with what that person told you. The expression -2(x+10) is equivalent to -2x-20

Multiply the outer -2 with the inner x to get -2 times x = -2x

Multiply the outer -2 with the inner term 10 to get -2 times 10 = -20

So overall, -2(x+10) = -2x-20

--------------------------------------------

So that's how we're able to go from this $-2(x+10) \ge 75$ to this $-2x-20 \ge 75$

The only thing that changes is the left side. The inequality sign will not flip. It only flips if we multiply both sides by a negative number.

erik [133]2 years ago

6 0

Answer:True

Step-by-step explanation:

Yes, you don't have to reverse the inequality symbol since the variables are not from the other side (right).

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3 years ago

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2 years ago

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stepan [7]

Answer:

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6 0

2 years ago

Factor a2 - 11a + 30

Schach [20]

Answer:

Factor a2 - 11a + 30

A) (6 - a)(5 - a)

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D) (a - 6)(a -5)

3 0

3 years ago

Read 2 more answers

The average American man consumes 9.8 grams of sodium each day. Suppose that the sodium consumption of American men is normally

Alex Ar [27]

Answer:

(a) The distribution of X is N (9.8, 0.8²).

(b) The probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

Step-by-step explanation:

The random variable X is defined as the amount of sodium consumed.

The random variable X has an average value of, μ = 9.8 grams.

The standard deviation of X is, σ = 0.8 grams.

(a)

It is provided that the sodium consumption of American men is normally distributed.

The random variable X follows a normal distribution with parameters μ = 9.8 grams and σ = 0.8 grams.

Thus, the distribution of X is N (9.8, 0.8²).

(b)

If X ~ N (µ, σ²), then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z ~ N (0, 1).

To compute the probability of Normal distribution it is better to first convert the raw score (X) to z-scores.

Compute the probability that an American consumes between 8.8 and 9.9 grams of sodium per day as follows:

$P(8.8$

$=P(-1.25$

Thus, the probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c)

The probability representing the middle 30% of American men consuming sodium between two weights is:

$P(x_{1}$

Compute the value of z as follows:

$P(-z$

The value of z for P (Z < z) = 0.65 is 0.39.

Compute the value of x₁ and x₂ as follows:

$-z=\frac{x_{1}-\mu}{\sigma}\\-0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8-(0.39\times 0.8)\\x_{1}=9.488\\x_{1}\approx9.5$ $z=\frac{x_{2}-\mu}{\sigma}\\0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8+(0.39\times 0.8)\\x_{1}=10.112\\x_{1}\approx10.1$

Thus, the middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

4 0

3 years ago