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hichkok12 [17]
3 years ago
7

HELP!!!!:(2.) WHAT'S THE RESULT?​

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
6 0

-1+5x

You combine like terms:

Here there are two different ones.

the number without the variable (the 1s) and the one with the variable (5x)

All you have to do is combine them:

1+(-1)+(-1) = 1-1-1 = -1

5x = 5x

So, the answer would be -1+5x

Hope this helps :D

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Given the following coordinates complete the reflection transformation.​
Minchanka [31]

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y ) , then

A (- 1, - 5 ) → A' (- 1, 5 )

B (2, - 3 ) → B' (2, 3 )

C (3, - 5 ) → C' (3, 5 )

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

A' (- 1, 5 ) → A'' (1, 5 )

B' (2, 3 ) → B'' (- 2, 3 )

C' (3, 5 ) → C'' ( - 3, 5 )

4 0
3 years ago
HELP I WILL MARK YOU AS A BRAINLIEST!!!
klasskru [66]

They give you the base value which makes this easy, the answer is B. 32, because 8 times 4 is 32.

Hope this helps, if not, comment below please!!!!

6 0
3 years ago
In need of help with functions in Algebra 2! Thank you!
Damm [24]

Answer: The answer should be B

6 0
3 years ago
There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
4 years ago
Question:
pishuonlain [190]
There is no rectangle shown.

To find area, you multiply the rectangle’s length by its width. If it comes out to be a decimal and you need to round it by the nearest tenth, then you round it to the right of the decimal point.

Ex: 2.34 -> 2.3

Then, to find how much square inches are equal to square ft, you divide the square inches by 12, I believe.
8 0
3 years ago
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