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Alekssandra [29.7K]
2 years ago
6

Write a quadratic function in standard form that passes through (-8, 0), (-2, 0), and (-6,8).

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
3 0

Answer:

-10xsquared-x+38

Step-by-step explanation:

so,

general eqn of quadratic equation is,

axsquared+bx+c=y

where,

x and y are exchanged by coordinates given in qn

1,64a-8b+c=0

2,4a-2b+c=0

or c=2b-4a

60a-6b=0

3,36a-6b+c=8

32a-4b=8

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atroni [7]
Hi there!

To find f(-2), we need to plug in the value x = -2 into the equation.

f( - 2) = ( - 2) {}^{2}  + 4 \times  - 2 = 4 - 8 =  - 4
Remember that multiplying a negative by a positive ends up with a positive.

~ Hope this helps you!
8 0
3 years ago
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3 years ago
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nadya68 [22]

Answer:

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3 years ago
SOMEONE PLEASE HELP ME
notka56 [123]
Area of deck= 2(20w)+4(w^2)+2(50w)d
456=2(20w)+4(w^2)+2(50w)

456=40w+4w^2+100w

456=4w^2+140w

114=w^2+35w

0=w^2+35w-114

find what 2 numbers multiply to get 114 and add to get 35 and factor

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0=(w-3)(w+38)

set each to zero

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3 0
3 years ago
A line passes through point (8, -8) and has a slope of -3/2 . Write an equation in Ax+By=C form for this line. Use integers for
olchik [2.2K]

y = -3/2(x) + b

-8 = -3/2(8) + b

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b = 4

y = -3/2(x) + 4

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Hope this helps!! :)

4 0
3 years ago
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