16 cubic inches or 13 oz.
Answer:
y-axis, x-axis, y-axis, x-axis
Step-by-step explanation:
Alright, so this problem looks a lot harder than it really is. When you flip a point across the x axis, y becomes negative, and when it is flipped across the y axis, x becomes negative. This means that if the x value changes signs it was flipped on the y axis, and vice versa.
Answer:
∠C ≅ ∠M or ∠B ≅ ∠L
Step-by-step explanation:
You are given an angle and its opposite side as being congruent. AAS requires two congruent angles and one side, so you need another set of congruent angles (one in each triangle). It does not matter which they are. The above-listed pairs are appropriate.*
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* Since the figure cannot be assumed to be drawn to scale, either of angles B or C could be declared congruent to either of angles L or M. However, it appears that angles B and L are opposite the longest side of the triangle, so it makes good sense to declare that pair congruent. The same congruence statement (ΔBCD≅ΔLMN) would result from declaring angles C and M congruent. So, either declaration will work (matches the last answer choice.)
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AAS requires two angles and a side. One side is already marked, so we do not need any more information about sides. (The second and third answer choices can be rejected as irrelevant.)
Answer:
d) x-intercept
Step-by-step explanation:
The zeros of a function are the values of x that make y = 0.
Thus, they are the points where the graph crosses the x-axis, that is, the x-intercepts.
a) is wrong. the y-intercept is simply the value of y when x = 0.
b) and c) are wrong. A quadratic can have only one maximum or one minimum; it can't have both. And they are not zeros except in the special case of y = ±ax².
The diagram below is the graph of y = x² + 3x - 46. It shows the zeros at x = -23 and x = 20. The minimum and the y-intercept are not zeros of the function.
Y^2+36, because you square y and 6
