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3 years ago

13

Simplify completely x2 + 4x - 45/x2 +10x+9 and find the restrictions on the variable.

1 answer:

murzikaleks [220]3 years ago

4 0

Answer:

The correct answer is,

${x}^{2} + 14x - \frac{45}{ {x}^{2} } + 9$

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tia_tia [17]

It should be the answer c

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3 years ago

Jason ordered the numbers −70, −18, and −18.5 from least to greatest by writing the following statement:

ser-zykov [4K]

Answer:

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Step-by-step explanation:

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3 years ago

Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =

Rainbow [258]

Answer:

$\sin L = 0.60$

$tan\ N = 1.33$

$\cos L = 0.80$

$\sin N = 0.80$

Step-by-step explanation:

Given

See attachment

From the attachment, we have:

$MN = 6$

$LN = 10$

First, we need to calculate length LM,

Using Pythagoras theorem:

$LN^2 = MN^2 + LM^2$

$10^2 = 6^2 + LM^2$

$100 = 36 + LM^2$

Collect Like Terms

$LM^2 = 100 - 36$

$LM^2 = 64$

$LM = 8$

Solving (a): $\sin L$

$\sin L = \frac{Opposite}{Hypotenuse}$

$\sin L = \frac{MN}{LN}$

Substitute values for MN and LN

$\sin L = \frac{6}{10}$

$\sin L = 0.60$

Solving (b): $tan\ N$

$tan\ N = \frac{Opposite}{Adjacent}$

$tan\ N = \frac{LM}{MN}$

Substitute values for LM and MN

$tan\ N = \frac{8}{6}$

$tan\ N = 1.33$

Solving (c): $\cos L$

$\cos L = \frac{Adjacent}{Hypotenuse}$

$\cos L = \frac{LM}{LN}$

Substitute values for LN and LM

$\cos L = \frac{8}{10}$

$\cos L = 0.80$

Solving (d): $\sin N$

$\sin N = \frac{Opposite}{Hypotenuse}$

$\sin N = \frac{LM}{LN}$

Substitute values for LM and LN

$\sin N = \frac{8}{10}$

$\sin N = 0.80$

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3 years ago

The formula for the area of a circle is A=pir^2. Find the area of a circle with a diameter of 6.4 centimeters. Use a calculator

Advocard [28]

A=pi(3.2)^2= 32.1699087728
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4 years ago