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Bogdan [553]
3 years ago
14

9y = 3y Combine the like terms

Mathematics
1 answer:
-BARSIC- [3]3 years ago
5 0
9y-3y=0
6y=0

Hope that helps
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5/2+18/5+11/4 what is the answer for this question​
Likurg_2 [28]

Answer:

Step-by-step explanation:

basicallyi you want to find a common denominator before you add them up. the common denominator in this case would be 20, since it's the first common multiple all of them share

50/20 plus 72/20 plus 55/20

177/20 would be your answer

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What is the answer to this math question -9.3÷2.5k=5.1
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That equation is (2.5×2). The mean of the K is ×2

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Find the product.<br> 2.05x0.47 =
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0.9625

Step-by-step explanation:

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Use properties of equality to simplify each of the following expressions so that you can simplify them in your head. Identify th
Salsk061 [2.6K]
Properties of equality have nothing to do with it. The associative and commutative properties of multiplication are used (along with the distributive property and the fact of arithmetic: 9 = 10 - 1).

All of these problems make use of the strategy, "look at what you have before you start work."


1. = (4·5)·(-3) = 20·(-3) = -60 . . . . if you know factors of 60, you can do this any way you like. It is convenient to ignore the sign until the final result.

2. = (2.25·4)·23 = 9·23 = 23·10 -23 = 230 -23 = 207 . . . . multiplication by 4 can clear the fraction in 2 1/4, so we choose to do that first. Multiplication by 9 can be done with a subtraction that is often easier than using ×9 facts.

4. = (2·5)·12·(-1) = 10·12·(-1) = (-1)·120 = -120 . . . . multiplying by 10 is about the easiest, so it is convenient to identify the factors of 10 and use them first. Again, it is convenient to ignore the sign until the end.

5. = 0 . . . . when a factor is zero, the product is zero
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4 years ago
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\bf \textit{middle point of 2 points }\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;X&({{ a}}\quad ,&{{ b}})\quad &#10;%  (c,d)&#10;Y&({{ -8}}\quad ,&{{ 6}})&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)

\bf \left( \cfrac{-8+a}{2}~,~\cfrac{6+b}{2} \right)=\stackrel{M}{(-3,-1)}\implies &#10;\begin{cases}&#10;\cfrac{-8+a}{2}=-3\\\\&#10;-8+a=-6\\&#10;\boxed{a=2}\\&#10;----------\\&#10;\cfrac{6+b}{2}=-1\\\\&#10;6+b=-2\\&#10;\boxed{b=-8}&#10;\end{cases}
5 0
3 years ago
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