Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So, 
is 37°. We can see from the diagram that 
would be 
143°.
Also, the new bearing is N 25°E. So, 
would be 25°.
Now we can find 
. As the sum of the internal angle of a triangle is 180°.
Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is 
We can apply the sine rule now.
So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
Well, you have to read 10 1/2 pages and you have read 1/3 so ask your self...Self what is 1/3 of 10 1/2 pages. The key word
of tells you to multiply the two numbers to find the answer. So
Answer: C y>3x+1
Step-by-step explanation:
- When we graph an inequality with strictly greater of less than sign ('<' or '>'), then the graph has a dashed boundary line .
- Further it indicates that it does not include the points on the line.
From all the given options , only C contains inequality with '>' sign .
Hence, y>3x+1 is the inequality has a dashed boundary line when graphed.
hence, the correct option is C.
The slope is the rate
words per minute
we can do
540 words in 3 minutes
divide by 3
180 words in 1 minute
thea=180wpm
elanor=225wpm
elanor>thea
and 225*2=450
answers are
Thea reads 180 words per minute.
Eleanor reads 450 words every 2 minutes.
After 1 hour of reading, Eleanor reads more words than Thea.
I think it would be 25t but correct me if i’m wrong
