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torisob [31]
2 years ago
13

I subtract 3 from a certain number, multiply the result by 5 and then add 9

Mathematics
2 answers:
viktelen [127]2 years ago
4 0

Answer:

<h2><u><em>5x - 6</em></u></h2>

Step-by-step explanation:

I subtract 3 from a certain number, multiply the result by 5 and then add 9

Remember PEMDAS

(x - 3) * 5 + 9 =

5x - 15 + 9 =

<u><em>5x - 6</em></u>

mr_godi [17]2 years ago
3 0

Answer:

  • The number is 5x-6

Step-by-step explanation:

Let the number be x.

Then,

Subtracting 3,

  • x - 3

Multiplying by 5,

  • (x-3)5
  • 5(x-3)

Adding 9:

  • 5(x-3)+9

Solving Further:

  • 5x-15+9
  • 5x-6
You might be interested in
The length of a rectangle is 1 more than 3 times the width . If the perimeter of the rectangle is 18 units , what’s it’s area?
nika2105 [10]

Answer:

14 square units

Step-by-step explanation:

You need to know the formulas for the perimeter of a rectangle and the area of a rectangle, which are

2L + 2W - P     where L is the length, W is the width, and P is the perimeter

and

A = LW      

So we need to find the length and width to find the area


Step 1:  Write equations out of the given information

"The length of a rectangle is 1 more than 3 times the width" can be rewritten as

L = 3W + 1


"the perimeter of the rectangle is 18 units" can be rewritten as

2L + 2W = 18


Step 2:  Plug the first formula into the second one and solve

      2(3W + 1) + 2W = 18

Simplify...

      6W + 2 + 2W = 18

Combine like terms and subtract 2 from both sides

     8W = 16

Divide both sides by 8 to isolate the W

   W = 2


Step 3:  

Plug W = 2 into the formula for L and solve for L

  L = 3(2) + 1

      L = 6 + 1

        L = 7


Step 4:  Use the length and width to calculate the area

A = LW

  A = (7)(2)

     A = 14 units squared

6 0
4 years ago
What is equivalent to m4 • m7
telo118 [61]

Answer:3.3

Step-by-step explanation:

m4*m7

3 0
3 years ago
-6*(-3) as a real life problem​
Mekhanik [1.2K]

Answer:

18

Step-by-step explanation:

-6 × (-3)

negative× negative= positive

so 18.

6 0
3 years ago
Calculator
mixas84 [53]

\text{Given : Which ordered pair is the solution to the system of equations?} \\  \\  \begin{cases}-5x - 3y = 12 \\   y - x = 12 \end{cases}

\text{Solution : According to the question, here let's take these variables as two}  \\  \text{equations then get their value and finally get the answer.} \\  \\  \sf  {1}^{st} \: equation  :  \\ \leadsto \frak{-5x - 3y = 12} \\  \\ \leadsto \frak{-5x = 12 + 3y} \\  \\ \leadsto \frak{x=  \frac{12 + 3y}{-5}} \qquad  \sf ...eq(1) \\  \\  \sf 2^{nd}  \: equation :  \\  \leadsto \frak{y = x - 12} \qquad \sf ...eq(2) \\  \\  \underline{  \frak{finding \: x  }} :  \\  \\  \dashrightarrow \frak{x=  \frac{12 + 3y}{-5}}  \\  \\ \dashrightarrow \frak{x=  \frac{12 + 3(x - 12)}{-5}}  \\  \\  \dashrightarrow \frak{x=  \frac{12 + 3x - 36}{-5}}  \\  \\  \dashrightarrow \frak{-5x=  12 + 3x - 36}  \\  \\  \dashrightarrow \frak{-5x - 3x=   - 24}  \\  \\  \dashrightarrow \frak{-8x =  - 24}  \\  \\  \star \quad \underline{ \boxed{ \green{ \frak{x =  3}}}} \\  \\ \underline{ \frak{ getting \: y}} : \\  \\  \dashrightarrow \frak{y = 3 - 12} \\  \\ \star  \quad\underline{  \boxed{\blue{ \frak{y =  - 9}}}} \\  \\

\green{ \mathbb{HENCEFORTH, \:  THE \:  PAIR \:  IS \:   \pink{\frak{ (3,-9)}}}}

5 0
3 years ago
Plz help asap!!!!<br> What is the midpoint of the segment shown below?
kifflom [539]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
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