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2 years ago

Look at the number line below. The letters f, g, h, and i all represent integers. Write two inequalities to compare f and g.

Mathematics

1 answer:

VladimirAG [237]2 years ago

8 0

I might be wrong but I think it’s f plus g

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Cos 4θ − cos 2θ = sin θ

hichkok12 [17]

$cos(4\theta) - cos(2\theta) = sin(\theta)$
$-2sin(\frac{4\theta + 2\theta}{2})sin(\frac{4\theta - 2\theta}{2}) = sin(\theta)$
$-2sin(\frac{6\theta}{2}sin\frac{2\theta}{2}) = sin(\theta)$
$-2sin(3\theta)sin(\theta) = sin(\theta)$
$\frac{-2sin(3\theta)sin(\theta)}{-2sin(\theta)} = \frac{sin(\theta)}{-2sin(\theta)}$
$sin(3\theta) = -\frac{1}{2}$
$sin^{-1}[sin(3\theta)] = sin^{-1}(-\frac{1}{2})$
$3\theta = -30$
$\frac{3\theta}{3} = \frac{-30}{3}$
$\theta = -10$

7 0

2 years ago

Complete the equation. Round to the nearest hundredth where necessary.

Alexandra [31]

Answer:

Step-by-step explanation:

There are 1.61 km in 1 mi.

10 mi × (1.61 km/mi) = 16.1 km

7 0

3 years ago

Answer the question in the picture pls WORTH 50 POINTS PLUS BRAINLIEST FOR FIRST CORRECT ANSWER

Alexus [3.1K]

Answer:

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

−y+4≥8

Step 2: Subtract 4 from both sides.

−y+4−4≥8−4

−y≥4

Step 3: Divide both sides by -1.

−y

−1

≥

−1

y≤−4

5 0

2 years ago

Read 2 more answers

NEED HELP WITH BOTH PLZ

Natalija [7]

For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8

7 0

3 years ago

Which ordered pair would form a proportional relationship with the point graphed below? (60,-20)

valentina_108 [34]

Given:

The graphed point is (60,-20).

To find:

The ordered pair that would form a proportional relationship with the given point.

Solution:

If y is proportional to x, then

$y\propto x$

$y=kx$

$\dfrac{y}{x}=k$

Where, k is the constant of proportionality.

For the given point,

$k=\dfrac{-20}{60}$

$k=\dfrac{-1}{3}$

For option (A),

$k=\dfrac{30}{-10}$

$k=-3\neq \dfrac{-1}{3}$

For option (B),

$k=\dfrac{-15}{30}$

$k=-\dfrac{1}{2}\neq \dfrac{-1}{3}$

For option (C),

$k=\dfrac{10}{-30}$

$k=\dfrac{-1}{3}$ .

The point (-30,10) gives the same value of the constant of proportionality. So, the point (-30,10) forms a proportional relationship with the given point.

Therefore, the correct option is C.

7 0

2 years ago